All categories

3 years ago

Why are the significantly more thunderstorms in Florida than in California?

2 answers:

8 0

The answer to your question is Thunderstorms are a frequent part of Florida life. They occur in all seasons of the year in Florida, but they are more numerous during the warm season when the wind off the sea flows inland during the afternoon. On an annual basis, communities in Florida usually experience thunderstorms 75 to 105 days per year. In fact, Florida leads the United States annually in the number of thunderstorm days. Out of 100,000 thunderstorms that occur within the United States each year, approximately 1 out of every 10 storms can become severe, causing damage or posing a threat to life. The average thunderstorm contains approximately 275 million gallons of water, which is enough water to fill 416 Olympic-sized swimming pools! <span>HOPED I HELPED!</span>

Andreyy893 years ago

3 0

Because Florida is wet and humid, while California is dry and non-humid. Florida also contains lots of lakes which evaporate to create thunderstorms.

You might be interested in

Find the intensity of electromagnetic radiation at the surface of the sun (radius r=R=6.96×105kmr=R=6.96×105km). Ignore any scat

alisha [4.7K]

Answer:

$I = 4.46*10^{16}W/m^2$ .

Explanation:

Intensity $I$ of the electromagnetic radiation is given by

$I = \dfrac{P}{4\pi r^2},$

where $r$ is the distance from the EM source (the center of the sun, in our case), and $P$ is the power output of the sun and it has the value

$P = 3.9 *10^{26}W.$

Since the radius of the sun in meters is $r = 6.96*10^8km$ , the intensity $I$ of the electromagnetic radiation at the surface of the sun is

$I = \dfrac{3.9*10^{26}W}{4\pi (6.96*10^8m)^2}\\\\\boxed{ I = 4.46*10^{16}W/m^2}$

The intensity of the electromagnetic radiation at the surface of the sun is $I = 4.46*10^{16}W/m^2$ .

7 0

3 years ago

suppose an electrically charged ruler transfers some of its charge by contact to a tiny plastic sphere. will the ruler and the s

poizon [28]

Answer:

Here ball and rod will repel each other as they are of similar charges

Explanation:

As we know that the two charges attract or repel each other by electrostatic force

This force is given as

$F = \frac{kq_1q_2}{r^2}$

so we know if two charges are similar in nature then they will repel each other and if the two charges are opposite in nature then they will attract each other

So here when rod touch the ball then it transfer its charge to the ball and due to similar charges in ball and rod they both repel each other

5 0

3 years ago

Minnie sota hits the end of a bar 1. 2 m long with a hammer. Sketch the standing wave on the bar for the following situations. T

ella [17]

(a) The wavelength of the wave for the fundamental mode is 2.4 m.

(b) The fundamental frequency of the wave is 2,708.33 Hz.

<h3>Wavelength of the wave for fundamental mode</h3>

The wavelength of the wave for the fundamental mode is calculated as follows;

Node to Node, N → N = λ/2

L = λ/2

λ = 2L

λ = 2 x 1.2

λ = 2.4 m

<h3>Fundamental frequency of the wave</h3>

The fundamental frequency of the wave is calculated as follows;

f = v/λ

f₀ = v/2L

f₀ = (6500)/(2 x 1.2)

f₀ = 2,708.33 Hz

The diagram of the wave for the fundamental mode is in the image uploaded.

Learn more about wavelength here: brainly.com/question/10728818

5 0

2 years ago

An object from which neither matter nor light can escape is called a _________.

vichka [17]

The correct answer is a blackhole.

A blackhole is the only object in which nothing, not even light can escape.

Hope this helps!

4 0

4 years ago

Read 2 more answers

Water pressurized to 3.5 x 105 Pa is flowing at 5.0 m/s in a horizontal pipe which contracts to 1/3 its former area. What are th

masha68 [24]

Answer:

the pressure after contraction is 2×10^5 Pa

the speed after contraction is 15m/s

Explanation:

We were given Pressure P to be 3.5 x 10^5 that is Flowing with speed of 5.0 m/s,

For us to calculate pressure we need to calculate the area first as;

Let initial Area = A₁

And Final area A₂

We were told that in a horizontal pipe it contracts to 1/3 its former area. Which means

A₂= A₁/3.................

V₁ is the speed

the pressure and speed of the water after the contraction can be calculated using equation of continuity below

A₂V₂ = A₁V₁

But

If we substitute given value in the expresion we have

V₂ = (3A *5)/A

V₂ = 15m/s

Therefore, the speed after contraction is 15m/s

Now we can calculate the pressure using

Bernoulli's equation

p₁ + ½ρv₁² + ρgh₁ = p₂ + ½ρv₂² + ρgh₂

But we know that the pipe is horizontal, then "h" terms cancel out then

p₁ + ½ρv₁² = p₂ + ½ρv₂²

Making P₂ subject of formula we have

p₂ = 0.5ρ( V ₁² - v₂² ) + P₁

P₂=. 0.5 × 1000 (5² -15² ) + 3*10^5

=2×10^5 Pa

Therefore, the pressure after contraction is 2×10^5 Pa

7 0

3 years ago