Answer:
constant speed or a horizontal line is an rest
Explanation:
The rate constant : b. 1/ M² · s
<h3>Further explanation </h3>
The reaction rate (v) shows the change in the concentration of the substance (changes in addition to concentrations for reaction products or changes in concentration reduction for reactants) per unit time.
For A + B ---> C + D
Can be formulated:
![\large{\boxed{\boxed{\bold{v~=~k.[A]^a[B]^b}}}](https://tex.z-dn.net/?f=%5Clarge%7B%5Cboxed%7B%5Cboxed%7B%5Cbold%7Bv~%3D~k.%5BA%5D%5Ea%5BB%5D%5Eb%7D%7D%7D)
where
v = reaction speed, M / s
k = constant, mol¹⁻⁽ᵃ⁺ᵇ⁾. L⁽ᵃ⁺ᵇ⁾⁻¹. S⁻¹
a = reaction order to A
b = reaction order to B
[A] = [B] = concentration of substances
Units of the rate constant - k depend on rate law, so it is unique for the specific reaction
So for the rate law :
Δ[C]/ΔT = k[A]²[B] , the units are :
![\tt \dfrac{M}{s}=k\times M^2\times M\\\\k=\dfrac{M/s}{M^2\times M}\\\\k=\dfrac{1}{M^2.s}](https://tex.z-dn.net/?f=%5Ctt%20%5Cdfrac%7BM%7D%7Bs%7D%3Dk%5Ctimes%20M%5E2%5Ctimes%20M%5C%5C%5C%5Ck%3D%5Cdfrac%7BM%2Fs%7D%7BM%5E2%5Ctimes%20M%7D%5C%5C%5C%5Ck%3D%5Cdfrac%7B1%7D%7BM%5E2.s%7D)
Answer:
79'420J
Explanation:
We know mass 250g and
∆T=98°C -22°C
=76°C
The specific heat capacity for water is 4,18Zj/g°C
THEREFORE
∆H=250g•14,8j/g°C •76°C
=79'420J
Answer:
1.67 moles of N2 produce 2.5moles of NaN3
Explanation:
Equation of reaction:
2Na + 3N₂ → 2NaN₃
From the equation of reaction, 3 moles of N₂ produces 2 moles of NaN₃
How much is gotten from 2.5moles of 2NaN₃?
2 moles of N₂ = 3 moles of NaN₃
X moles of N₂ = 2.5 moles of NaN₃
X = (2.5 × 2) / 3
X = 1.67moles of N₂
1.67 moles of N₂ produces 2.5moles of NaN₃