Answer:
Specific Heat Capacity = 0.901 J.g⁻¹.°C⁻¹
Heat is Exothermic
Explanation:
Specific heat capacity is the amount of heat required to raise the temperature of a given amount of substance by one degree.
Also, Exothermic reactions are those reaction in which the heat is lost from the system to surrounding while, endothermic reactions are those in which the system gains heat from the surroundings.
The equation used for this problem is as follow,
Q = m Cp ΔT ----- (1)
Where;
Q = Heat = 14200 J
m = mass = 350 g
Cp = Specific Heat Capacity = ??
ΔT = Change in Temperature = 70 °C - 25 °C = 45 °C
Solving eq. 1 for Cp,
Cp = Q / m ΔT
Putting values,
Cp = 14200 J / (350 g × 45 °C)
Cp = 0.901 J.g⁻¹.°C⁻¹
As the heat is lost by the metal therefore, the heat is exothermic.
B. A chemical change has occurred and energy was given off
Answer: The equilibrium constant for the given reaction is 0.0421.
Explanation:

Concentration of
= 0.0095 M
Concentration of
= 0.020 M
Concentration of
= 0.020 M
The expression of the equilibrium constant is given as:
![K_c=\frac{[PCl_3][Cl_2]}{[PCl_5]}=\frac{0.020 M\times 0.020 M}{0.0095 M}](https://tex.z-dn.net/?f=K_c%3D%5Cfrac%7B%5BPCl_3%5D%5BCl_2%5D%7D%7B%5BPCl_5%5D%7D%3D%5Cfrac%7B0.020%20M%5Ctimes%200.020%20M%7D%7B0.0095%20M%7D)
(An equilibrium constant is an unit less constant)
The equilibrium constant for the given reaction is 0.0421.
Answer:
The answer is: Molecule and Organ system.