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3 years ago

Selecting resources with reliable credentials and expertise is?

Chemistry

2 answers:

Zina [86]3 years ago

6 0

Answer: D. Important for any information you look up, on any topic.

Explanation:

The resources can be considered as reliable and credentials when they consists of information which comes from an authentic source. Also the resource which has been verified by many reviewers who exhibit special knowledge and expertise in the related field of the topic can be considered as reliable and credential.

Such a resource can be looked upon for retrieving desired information on any topic.

PtichkaEL [24]3 years ago

5 0

Answer:its D

Explanation:

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Predict the products of hydrobromic acid, H B r , reacting with magnesium hydroxide, M g ( O H ) 2 . Select one or more:

Aliun [14]

Answer:

Magnesium bromide, MgBr2, and water, H2O.

Explanation:

Hello!

In this case, since HBr is an acid and Mg(OH)2 is a base, an acid-base reaction is undergone, by which a salt and water are produced as neutralization products:

$HBr+Mg(OH)_2\rightarrow MgBr_2+H_2O$

However, it need to be balanced since two bromine atoms are produced, therefore we write:

$2HBr+Mg(OH)_2\rightarrow MgBr_2+2H_2O$

Thus, the products are magnesium bromide, MgBr2, and water, H2O.

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6 0

3 years ago

A substance has twice the number of particles as 12 grams of carbon-12. How many

klasskru [66]

Answer:

D)2.0

Explanation:

Avogadro’s number represent the number of the constituent particles which are present in one mole of the substance. It is named after scientist Amedeo Avogadro and is denoted by $N_0$ .

Also, it is the number of particles in exactly 12.000 g of isotope carbon 12.

Avogadro constant:-

$N_a=6.023\times 10^{23}$

Thus,

Number of particles as 12 grams of carbon-12 constitutes 1 mole

<u>Twice the number of particles as 12 grams of carbon-12 constitutes 1*2 mole</u>

Thus, moles in the substance = 2.0 moles

3 0

3 years ago

Mass number of 24 and 13 neutrons

olasank [31]

More information, please!

7 0

3 years ago

Suppose 12.0 g of carbon (c) reacts with 70.0 g of sulfur (s) to give 76.0 g of the compound carbon disulfide 1 c s 2 2 . In the

Nitella [24]

Answer is: mass of unused sulfur is 5.87 grams.

Balanced chemical reaction: C + 2S → CS₂.

m(C) = 12.0 g; mass of carbon.

m(S) = 70.0 g; mass of sulfur.

n(C) = m(C) ÷ M(C).

n(C) = 12 g ÷ 12 g/mol.

n(C) = 1 mol; amount of substance.

n(S) = m(S) ÷ M(S).

n(S) = 70 g ÷ 32.065 g/mol.

n(S) = 2.183 mol.

From chemical reaction: n(C) : n₁(S) = 1 : 2.

n₁(S) = 1 mol · 2 = 2 mol.

Δn(S) = n(S) - n₁(S).

Δn(S) = 2.183 mol - 2 mol.

Δn(S) = 0.183 mol; amount of unused sulfur.

Δm(S) = 0.183 mol · 32.065 g/mol.

Δm(S) = 5.87 g.

4 0

3 years ago

If 20.0 g of magnesium react with excess hydrochloric acid, how many grams of magnesium chloride are produced? ____Mg + ____HCl

gtnhenbr [62]

Explanation:

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8 0

3 years ago