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aliya0001 [1]
3 years ago
9

Selecting resources with reliable credentials and expertise is?

Chemistry
2 answers:
Zina [86]3 years ago
6 0

Answer: D. Important for any information you look up, on any topic.

Explanation:

The resources can be considered as reliable and credentials when they consists of information which comes from an authentic source. Also the resource which has been verified by many reviewers who exhibit special knowledge and expertise in the related field of the topic can be considered as reliable and credential.  

Such a resource can be looked upon for retrieving desired information on any topic.  

PtichkaEL [24]3 years ago
5 0

Answer:its D

Explanation:

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Water exists in three different states (solid, liquid, gas) at different temperatures. According to the graph water exists in wh
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Answer: Water

Explanation: I don't see any graph attached, but water has a boiling point of 100C, which is where it would become gas, or water vapor. 0C is the freezing point of water, where it would become ice. Since 50C is in the middle, it would be considered liquid.

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What is the hydronium ion concentration of a solution whose pH is 4.12?
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Compare and contrast the concepts of average mass and relative mass​
Sphinxa [80]

Answer:

Relative and average atomic mass both describe properties of an element related to its different isotopes. However, relative atomic mass is a standardized number that's assumed to be correct under most circumstances, while average atomic mass is only true for a specific sample.

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4 years ago
How many moles of potassium nitrate, KNO3 are present in a sample with a mass of 85.2 g?
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5 0
3 years ago
A block of aluminum weighing 140 g is cooled from 98.4°C to 62.2°C with the release of 1080 joules of heat. From this data, calc
GrogVix [38]

<u>Answer:</u>

Specific heat of a substance is the value that describe how the added heat energy of substance has the impact on its temperature.

Unit is <em>(\frac {J}{Kg.K})</em>

<em>C = Q/m. ∆T</em>

<em>C – Specific heat (\frac {J}{Kg.K})</em>

<em>Q- heat energy (J)</em>

<em>M – Mass (Kg)</em>

<em>∆T- change in temperature (K) </em>

<u>Explanation:</u>

<em>Given data:</em>

<em>M= 140 g = 0.14 Kg</em>

<em>Q – 1080 Joules.</em>

<em>∆T – 98.4 – 62.2 = 36.2</em>

Substituting  the given data in Equation

<em>Specific heat of Aluminium  = \frac {1080}{(0.14 \times 36.2)} = 213.10 (\frac {J}{Kg.K})</em>

3 0
3 years ago
Read 2 more answers
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