Answer:
So a compound is 52% Zinc(Zn), 9.6% Carbon(C), and 38.4% Oxygen (O). Let’s first start off by assuming that we have 100 g of this compound. This means that we have 52 g of Zinc, 9.6 g of Carbon, and 38.4 g of Oxygen.Zinc = 65.38 g/molCarbon = 12 g/molOxygen = 16 g/molThis means we have:52 g of Zn(1 mol Zn/65.38 g of Zn) ≈0.8 mol of Zn.9.6 g of C(1 mol C/12 g of C) = 0.8 mol of C38.4 g of O(1 mol of O/16 g of O) = 2.4 mol of O.
Explanation:
What we want to do next is divide each element by the common factor of all of them, which is 0.8. In most cases, you divide each element by the element with the least amount of moles. After we divide each by 0.8, you’ll notice you have 1 Zn, 1 C, and 3 O. This gives you the empirical formula of ZnCO3, or Zinc Carbonate.
Answer:
3= Lithium (Li) = [He] 2s1
6= Carbon (C) = [He] 2s2 2p2
8=Oxygen (O)= [He] 2s2 2p4
13=Aluminium (Al)= [Ne] 3s2 3p1
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Answer:
144cm²
Explanation:
Given dimensions:
Length x breadth x thickness
18cm x 8cm x 5cm
The widest part of this figure will be the face containing the length and the breadth.
The breadth is the width of the figure;
Area of the widest part = length x breadth = 18cm x 8cm = 144cm
The area of the widest part of the figure is 144cm²
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