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DaniilM [7]
3 years ago
13

Which answer best describes how to solve this story problem? A local store plans to put three coupons in each mailbox on a stree

t. The right side of the street has 16 mailboxes. The left side of the street has 17 mailboxes. How many coupons is the local store putting in mailboxes? A. Multiply 16 by 17. Add 3 to the product. B. Multiply 16 by 3. Multiply 17 by 3. Add the products. C. Add 16 and 3. Add 17 and 3. Multiply the sums.
Mathematics
2 answers:
shusha [124]3 years ago
6 0
You would want to multiply 16 by 3 and then multiply 17 by 3 and after that add them together.
Semmy [17]3 years ago
4 0
You want to multiply 16 times 3 which is 48 then 17 times 3 which is 51 then add them up and you get 99 which is the answer
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F(x) = 15,000(.84) shows the value of a car each year. Describe the following:
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Answers:

  • a) 15000 represents the starting amount
  • b) The decay rate is 16%, which means the car loses 16% of its value each year.
  • c) x is the number of years
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Explanation:

We have the function f(x) = 15000(0.84)^x. If we plug in x = 0, then we get,

f(x) = 15000(0.84)^x

f(0) = 15000(0.84)^0

f(0) = 15000(1)

f(0) = 15000

In the third step, I used the idea that any nonzero value to the power of 0 is always 1. The rule is x^0 = 1 for any nonzero x.

So that's how we get the initial value of the car. The car started off at $15,000.

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The growth or decay rate depends entirely on the base of the exponential, which is 0.84; compare it to 1+r and we see that 1+r = 0.84 solves to r = -0.16 which converts to -16%. The negative indicates the value is going down each year. So we have 16% decay or the value is going down 16% per year.

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The value of x is the number of years. In the first section, x = 0 represented year 0 or the starting year. If x = 1, then one full year has passed by. For x = 2, we have two full years pass by, and so on.

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The value of f(x) is the value of the car after x years have gone by. We found that f(x) = 15000 when x = 0. In other words, at the start the car is worth $15,000. Plugging in other x values leads to other f(x) values. For example, if x = 2, then you should find that f(x) = 10584. This means the car is worth $10,584 after two years.

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