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2 years ago

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PLS HELP Hannah and Brooklyn are two of the partners in a business. Hannah makes $3 in profit for every $4 that Brooklyn makes.

If their total profit on the first item sold is $105, how much profit does Hannah make? *

1 answer:

Dennis_Churaev [7]2 years ago

5 0

Answer:

77$

Step-by-step explanation:

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Over the interval 2 to 4 by how much does the function increse

gulaghasi [49]

The answer is 2 because two plus two equals 4 and 4-2=2 so the answer is 2. Hope this could help a lot and this was a useful answer

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3 years ago

Lamonte has 80 cents, Maggie has 3/4 of a dollar Gus is has two dimes and a nickle, and beau has six six dimes. Who has the most

Ulleksa [173]

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2 years ago

Batteries come in packs of 4. Last month, Joe used 58 batteries in his remote control drone. How many packs of batteries did he

vovangra [49]

It is given that batteries come in a packs of 4. It means in each pack there are 4 batteries.

Joe used 58 batteries . So to find the total number of packets of batteries joe has to open is

Number of batteries used / Total number of batteries in each packet

= 58 / 4

= 14.5

The number of battery can not be in decimal. So we will round the answer to integer. If we round it to 14 it means 14 packets. But in 14 packets there are 14*4 = 56 batteries .

But we know that Joe used 58 batteries. So we will round the final answer to 15.

It means Joe has to open 15 packets of batteries.

8 0

2 years ago

Use the information provided to determine a 95% confidence interval for the population variance. A researcher was interested in

Leno4ka [110]

Answer:

The 95% confidence interval for the population variance is (8.80, 32.45).

Step-by-step explanation:

The (1 - <em>α</em>)% confidence interval for the population variance is given as follows:

$\frac{(n-1)\cdot s^{2}}{\chi^{2}_{\alpha/2}}\leq \sigma^{2}\leq \frac{(n-1)\cdot s^{2}}{\chi^{2}_{1-\alpha/2}}$

It is provided that:

<em>n</em> = 20

<em>s</em> = 3.9

Confidence level = 95%

⇒ <em>α</em> = 0.05

Compute the critical values of Chi-square:

$\chi^{2}_{\alpha/2, (n-1)}=\chi^{2}_{0.05/2, (20-1)}=\chi^{2}_{0.025,19}=32.852\\\\\chi^{2}_{1-\alpha/2, (n-1)}=\chi^{2}_{1-0.05/2, (20-1)}=\chi^{2}_{0.975,19}=8.907$

*Use a Chi-square table.

Compute the 95% confidence interval for the population variance as follows:

$\frac{(n-1)\cdot s^{2}}{\chi^{2}_{\alpha/2}}\leq \sigma^{2}\leq \frac{(n-1)\cdot s^{2}}{\chi^{2}_{1-\alpha/2}}$

$\frac{(20-1)\cdot (3.9)^{2}}{32.852}\leq \sigma^{2}\leq \frac{(20-1)\cdot (3.9)^{2}}{8.907}\\\\8.7967\leq \sigma^{2}\leq 32.4453\\\\8.80\leq \sigma^{2}\leq 32.45$

Thus, the 95% confidence interval for the population variance is (8.80, 32.45).

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2 years ago

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Mila [183]

Answer:

37.5%

Step-by-step explanation:

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