Newton's Law of Cooling:

Temperature given at a time
Time
Surrounding temperature
Initial temperature
Constant (Euler's number) ≈ 2.72
Constant
Using this information, find the value of
, to the nearest thousandth, then use the resulting equation to determine the temperature of the water cup after 4 minutes.
First, plug in the given values in the equation and solve for
:
197°,
1.5 minutes,
70° and
210°

≈ 
Let the temperature of the water cup after
minutes be 
Now, let's plug the new time and
constant in the equation and solve for
:




![x=70+{\frac{140}{\sqrt[50]{e^{13}}}\\](https://tex.z-dn.net/?f=x%3D70%2B%7B%5Cfrac%7B140%7D%7B%5Csqrt%5B50%5D%7Be%5E%7B13%7D%7D%7D%5C%5C)

≈ 
Temperature of water after 4 minutes is 178°
sorry if there's any misspelling or wrong step but I hope my answer is correct ':3
3x is the miles from downstream
4 (x - 1) is the return trip
Solution:
3x = 4 (x - 1)
3x =4x - 4
-x = -4
x = 4
The outward journey 3x = 12 miles
Return journey is same length
Therefore the distance travel is 24 miles
Notice how the problem states that the marbles are being placed back into the bag which means you are on the right track but the denominators are the same.
3/11 times 3/11 times 5/11 which gives us the answer of 45/1131