Cu + 2H2SO4 ⟶ CuSO4 + SO2 + 2H20
In left hand side of the equation.
Cu = 1 atom
H = 4 atoms
S = 2 atoms
O = 8 atoms
In right hand side of the equation.
Cu = 1 atom
S = 2 atoms
0 = 8 atoms
H = 4 atoms
• All the atoms are balanced in the left and right side of the equation and it satisfies the law of conservation of mass.
• Equation is balanced and correct.
*See the attachment .
Molar mass HCl = 36.5 g/mol
number of moles:
mass of solute / molar mass:
9.63 / 36.5 => 0.263 moles
Volume = 1.5 L
M = n / V
M = 0.263 / 1.5
M = 0.1753 mol/L
espero ter ajudado!
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