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Papessa [141]
3 years ago
14

Naming chlorine as an Ion

Chemistry
1 answer:
Katarina [22]3 years ago
4 0

The name of the ion is chloride.

To name a <em>monatomic anion</em>

• <em>Drop the ending</em> of the element name (chlor<u>ine</u> → chlor)

• <em>Add the ending</em> <em>ide</em> (chlor + ide → chloride)

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. The element with the following
Ksenya-84 [330]

Explanation:

(a) Chlorine the first row Is 1s the second is 2s followed by 2p...etc as Chlorine has 17 electrons

7 0
3 years ago
​If a bag of peas weighs 454 grams, how many peas would be in the bag?
OverLord2011 [107]

​In a bag of peas that weighs 454 grams, there are between 1261 and 4540 peas.

The average pea weighs between 0.1 and 0.36 grams.

If we take the lower value (0.1 g/pea), the number of peas in 454 g is:

454 g \times \frac{1pea}{0.1 g} = 4540pea

If we take the higher value (0.36 g/pea), the number of peas in 454 g is:

454 g \times \frac{1pea}{0.36 g} \approx  1261pea

​In a bag of peas that weighs 454 grams, there are between 1261 and 4540 peas.

You can learn more about conversion factors here: brainly.com/question/1844638

6 0
3 years ago
One mole of ar initially at 305 k undergoes an adiabatic expansion against a pressure pexternal = 0 from a volume of 8.5 l to a
PilotLPTM [1.2K]
An adiabatic process is when the system is insulated that no heat is released to the surroundings. For this type of process, we have a derived formula written below:

(T₂/T₁)^C = (V₁/V₂)
where C = Cv/nR

From the complete problem shown in the attached picture, Cv = (3/2)R. Thus,
C= (3/2)/1 mol = 3/2

(T₂/305 K)^(3/2) = (8.5 L/82 L)
Solving for T₂,
<em>T₂ = 67.3 K</em>

3 0
3 years ago
Analysis of the water content of a lake found in the desert showed that it contained 16.6 percent chloride ion, and had a densit
IRISSAK [1]

Answer : The molarity of the chloride ion in the water is, 5.75 M

Explanation :

As we are given that 16.6 % chloride ion that means 16.6 grams of chloride ion present 100 grams of solution.

First we have to calculate the volume of solution.

\text{Volume of solution}=\frac{\text{Mass of solution}}{\text{Density of solution}}

\text{Volume of solution}=\frac{100g}{1.23g/mL}=81.3mL

Now we have to calculate the molarity of chloride ion.

Molarity : It is defined as the number of moles of solute present in one liter of volume of solution.

Formula used :

\text{Molarity}=\frac{\text{Mass of chloride ion}\times 1000}{\text{Molar mass of chloride ion}\times \text{Volume of solution (in mL)}}

Now put all the given values in this formula, we get:

\text{Molarity}=\frac{16.6g\times 1000}{35.5g/mole\times 81.3mL}=5.75mole/L=5.75M

Thus, the molarity of the chloride ion in the water is, 5.75 M

8 0
3 years ago
4. Will the net force be balanced or unbalanced?<br> 7N<br> 4N<br> A. Balanced<br> B. Unbalanced
o-na [289]

Answer:

Unbalanced

Explanation:

The force applied is not the same

8 0
4 years ago
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