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Alexxandr [17]
3 years ago
10

Some beads were in a box. Anne used 17 of them. Then there were 56 beads in the box. How many were in the box to begin with?

Mathematics
1 answer:
nekit [7.7K]3 years ago
3 0
There where 73 beads to begin with.
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X² - 16x + 17 = 0
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(x - 8)² - 64 + 17 = 0
(x - 8)² - 47 = 0 

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Answer: y = (x - 8)² - 47 (Answer D)
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Njh<br><br><br><br><br><br> by how many is 3 fours of 20 greater than 3 fiths of 20?
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To calculate a fraction of a quantity, multiply the quantity by the numerator of the fraction and divide by the denominator

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A store sells black ink pens for $5 and red ink pens for $4. John wishes to buy 20 pens but doesn’t wish to spend more than $92.
Zina [86]

Answer:  4r + 5(20-r) \le 92

=======================================

Explanation:

r = number of red pens

4r = cost of buying r red pens

example: if r = 10, then 4r = 4*10 = 40 is the total cost of buying 10 red pens

If John buys r red pens, then he must buy 20-r black pens so that r and 20-r add to 20.

John buys 20-r black pens, and at $5 each, so it will cost 5(20-r) dollars for just the black pens alone.

In total, John spends 4r + 5(20-r) dollars for all the pens (red & black)

We want $92 be the most he spends. This is the ceiling or highest value possible.

Therefore,

4r + 5(20-r) \le 92

--------------------

Extra info:

If you want to solve for r, then

4r + 5(20-r) \le 92

4r + 5(20)+5(-r) \le 92 distribute

4r + 100 - 5r \le 92  

100 - r \le 92

100-r+r \le 92+r add r to both sides

100 \le 92+r

100-92 \le 92+r-92 subtract 92 from both sides

8 \le r

r \ge 8

So John must buy at least 8 red pens. The most he can buy is 20 red pens since he wants 20 pens total.

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