ASAP someone please use the Pythagorean Theorem to solve for the missing side of these two right triangles.
1 answer:
Answer:
9) x = 5
10) x = 4
Step-by-step explanation:
a^2 + b^2 = c^2
9) 6^2 + x^2 = 8^2
- 36 + x^2 = 64
- 36 - 36
_______________
x^2 = 28
Square root them
Squareroot x^2 is x
Square root 28 is 5.29 round is 5
so x = 5
*Correct me if im wrong*
10) 3^2 + x^2 = 5^2
9 + x^2 = 25
- 9 - 9
____________________
x^2= 16
Square root them
square root of x ^2 is x and square root of 16 is 4
so x = 4
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Step-by-step explanation:
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Hope I helped!