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Andrew [12]
4 years ago
12

Consider the combustion of octane:

Chemistry
1 answer:
just olya [345]4 years ago
5 0

Answer:

15.9 g

Explanation:

(Take the atomic mass of C=12.0, H=1.0, O=16.0)

no. of moles = mass / molar mass

no. of moles of octane used = 11.2 / (12.0x8 + 1x18)

= 0.0982456 mol

Since oxygen is in excess and octane is the limiting reagent, the no. of moles of H2O depends on the no. of moles of octane used.

From the balanced equation, the mole ratio of octane : water = 2:18 = 1: 9,

so this means, one mole of octane produced 9 moles of water.

Using this ratio, we can deduce that (y is the no. of moles of water produced):

\frac{1}{9} =\frac{0.0982456}{y}

y = 0.0982456x9

y= 0.88421 mol

Since mass = no. of moles x molar mass,

mass of water produced = 0.88421  x (1.0x2+16.0)

=15.9 g

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nadya68 [22]
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5 0
3 years ago
1. What is the density of a 20 gram of 40 ml liquid?
____ [38]

Answer:

1. 0.5 g/mL

2. 0.88 g/cm^3

3. It has the greatest mass to volume ratio

4. Incomplete

5. H^+ (aq)+OH^-(aq)\rightleftharpoons H_2O (l)

6. 1

7. Gloves, goggles, coat, mask

8. Flush with tap water for at least 15 minutes

9. The facts are listed below

10. Mass and volume

12. All matter consists of moving particles, the degree of their movement is directly proportional to their kinetic energy

Explanation:

1. In order to solve for density, we should know that density is the ratio between mass and volume of a liquid. In this case, we're given both measures: given mass of m = 20 g and volume of V = 40 mL, we may simply apply the equation of density described here:

d=\frac{m}{V}

Substituting the variables, we obtain:

d=\frac{m}{V}=\frac{20 g}{40 mL}=0.5 g/mL

2. Given a mixture of several liquids, it's important to understand that liquids with a greater density will tend to form a bottom layer of a solution, while liquids with a lower density will tend to form a top layer of a solution. Here we have a liquid with a density of d_1 = 1.0 g/cm^3 and another liquid with a density of d_2 = 0.88 g/cm^3. Notice that d_1 > d_2.

This implies that the liquid with a density of 0.88 g/cm^3 would be on top, as its density is lower than the density of the other liquid with a density of 1.0 g/cm^3.

3. The solid phase is not always, but typically denser than liquids or gases. There are some exceptions to this rule, for example, ice, a solid phase of water, is less dense than liquid water.

However, for the majority of cases this statement is true. Remember that solid phases are the most ordered phases with atoms being packed closely to each other. In liquids, atoms are more dispersed with distances between them being greater than those in solids. Similarly, gases have the greatest distances between gas atoms among all three phases.

Since density is directly proportional to mass, let's say we take the same volume of a solid, a liquid and a gas. For the same volume, since we'll have a greater number of solid atoms than for a liquid or a gas (because solid atoms are more closely packed with lower average distances between the atoms), the mass to volume ratio will be the greatest for solids.

4. This seems to be an incomplete question.

5. In order to balance the following ionic equation, we need to follow the mass and charge balancing rules. Firstly, expand a water molecule showing the individual parts of it:

H-OH

Secondly, notice that we need to add a hydroxide anion to the proton, so that we obtain the same number of protons and hydroxide anions on the left side, as well as the number of hydrogen and oxygen atoms on the right. This way, the net charge on the left hand side (0) and the net charge on the right hand side (0) are equal, so the charge is balanced as well. We obtain:

H^+ (aq)+OH^-(aq)\rightleftharpoons H_2O (l)

6. We should be familiar with the ionization constant of water in the context of this problem. It is defined as the product between the hydronium ions and hydroxide ions and is a constant number at some given temperature. For pure water, the concentration of hydronium ions is balanced by the concentration of hydroxide anions to yield a neutral pH value, meaning the ratio of one with respect to the other would be 1.

For example, at room temperature, the ionization constant of water is defined as:

K_w=[H^+][OH^-]=10^{-14}

Since we have pure water:

[H^+]=[OH^-]=\sqrt{10^{-14}}=10^{-7}

Then the ratio is:

[tex]\frac{[H^+]}{[OH^-]}=\frac{10^{-7}}{10^{-7}}=1

7 to 12. The questions are explained in the file attached.

Download pdf
4 0
4 years ago
A solution contains the ions Ag , Pb2 , and Ni2 . Dilute solutions of NaCl, Na2SO4, and Na2S are available to separate the posit
Delicious77 [7]

Answer:

The solutions should be added in this order NaCl > Na2SO4 > Na2S

Explanation:

Silver is insoluble as a chloride, so the silver ions get precipitated on addition of chloride ion as silver chloride.  This means Ag+ would be removed the first.

So we will add NaCl in the first step.

The following reaction will occur.

Ag+ + Cl- → AgCl(s)

Both, Pb2 and Ni are soluble as chlorides. (lead chloride is soluble as a hot solution but will ppt when colder).

When we add Na2SO4, Pb2+ will get precipitated (because it's insoluble) as PbSO4 and Ni will remain soluble as NiSO4 is soluble in water.

The reaction that will occur is:

Pb^2+ + SO4^2- → PbSO4(s)

Nickel is insoluble as a sulfide. So when we will add Na2S, nickel will be precipitated as sulfide and be able to separate and be collected.

The solutions should be added in this order NaCl > Na2SO4 > Na2S

6 0
4 years ago
atomic mass of oxygen according to conventional scale is 16u. if we change the scale from 1/12 to 1/3 then its atomic mass will
Ipatiy [6.2K]

Answer:

The new atomic mass of oxygen is 64u

Explanation:

Given

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Now, when the scale is changed from 1/12 to 1/3, the new mass would become

\frac{16}{\frac{1}{12} } * \frac{1}{3} \\= \frac{16 * 12}{3} \\= 64

The new atomic mass of oxygen is 64u

3 0
3 years ago
An exothermic reaction _____.
pychu [463]
C. releases less energy than it uses
8 0
3 years ago
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