All categories

3 years ago

Explain the various factors that impact the solubility of substances in water.

Chemistry

2 answers:

Mashutka [201]3 years ago

5 0

Answer

Hi, the factors are;

Temperature

molecular size of solute

stirring

Explanation

An increase in temperature increases the solubility rate.Large solute molecules have larger molecular weight and size, thus less soluble. Stirring increases the speed of the dissolving process. In addition, polarity affects solubility in that solutes dissolve in solvents that share similar polarity.

All the best!

Andreyy893 years ago

5 0

Answer: Temperature, Molecular Size of the particle, Polarity, Stirring

Explanation: Solubility of substances in water depends upon the below mentioned factors -

1. Temperature - Higher the temperature, higher will be the kinetic energy of the particles which will move in random directions. Thus the particle will nt remain as precipitate in the solution and will try to get dissolved.

2. Molecular Size of the particle - It is more difficult for the solvent to dissolve the particle with large molecular size as it will take high temperature to get dissolved.

3. Polarity - 'Like dissolves like' explains the polarity concept of the solubility. It means that the non polar solute will get dissolved in non polar solvents and polar solutes will get dissolved in polar solvents only.

4. Stirring - Stirring only helps to increase the speed of the process of solubility. It has nothing to do with the substance.

You might be interested in

I think I put my in it when I asked Jane about her ex-husband<br>root<br>

ryzh [129]

What does this mean?

3 0

2 years ago

What causes atoms to form covalent bonds?

tino4ka555 [31]

Sharing of valence electrons.

Explanation:

In a covalent bonds, there is sharing of the valence electrons used in bonding between the two combining species.

The atoms taking part do not have a wide electronegativity difference between them and so they share the valence electrons to complete their octet and ensure their stability.

For the formation of this bond type, each of the atom requires a odd or unpaired electrons.
Covalent bonds are formed between atoms having zero or very small electronegativity difference.

Learn more:

Covalent bonds brainly.com/question/10903097

#learnwithBrainly

6 0

3 years ago

When 1.00 g of boron is burned in o2(g) to form b2o3(s), enough heat is generated to raise the temperature of 733 g of water fro

Bas_tet [7]

<span>Answer: For this problem, you would need to know the specific heat of water, that is, the amount of energy required to raise the temperature of 1 g of water by 1 degree C. The formula is q = c X m X delta T, where q is the specific heat of water, m is the mass and delta T is the change in temperature. If we look up the specific heat of water, we find it is 4.184 J/(g X degree C). The temperature of the water went up 20 degrees. 4.184 x 713 x 20.0 = 59700 J to 3 significant digits, or 59.7 kJ. Now, that is the energy to form B2O3 from 1 gram of boron. If we want kJ/mole, we need to do a little more work. To find the number of moles of Boron contained in 1 gram, we need to know the gram atomic mass of Boron, which is 10.811. Dividing 1 gram of boron by 10.811 gives us .0925 moles of boron. Since it takes 2 moles of boron to make 1 mole B2O3, we would divide the number of moles of boron by two to get the number of moles of B2O3. .0925/2 = .0462 moles...so you would divide the energy in KJ by the number of moles to get KJ/mole. 59.7/.0462 = 1290 KJ/mole.</span>

7 0

3 years ago

Each chemical element has an atomic number and a mass number. the atomic number refers to the number of ___________________the e

creativ13 [48]

The atomic number tells us the number of protons and electrons.
The atomic mass tells us the weight of the nucleus, which is the amount of protons and neutrons

5 0

3 years ago

What is the concentration of a solution containing 1.11 g sugar (sucrose, C12H22O11, MW = 342.3 g/mol, d = 1.587 g/cm3) in 432 m

djyliett [7]

Answer:

0.0075 M

0.0060 m

Explanation:

Our strategy here is to use the definition of molarity and molality to solve this question.

The molarity is the number of moles of solute, sucrose in this case, per liter of solution.

The molality is the number of moles of solute per kilogram of solvent.

So the molarity of the solution is

M = moles of solute/ V solution

As we see we need the volume of solution since we are only given the volume of solvent, but this will be easy to compute since we have the density of sucrose.

So determine the moles of sucrose , and the volume of solution:

Moles sucrose = 1.11 g/342.3 g/mol = 3.24 x 10⁻³ M

Volume of solution = Vol Sucrose + Vol glycerine

d = m/V ⇒ Vsucrose = m / d = 1.11 g/ 1.587 g/cm³ = 0.70 cm³

Vol solution = 432 mL + 0.70 mL = 432.7 mL (1cm³ = 1 mL)

Vol solution = 432.7 mL x 1 L / 1000 mL = 0.4327 L

⇒ M = 3.2 x 10⁻³ mol / 0.4327 L = 0.0075 M

For the molarity what we need is to first calculate the kilograms of glycerine from the given density:

d = m/v ⇒ m = d x v = 1.261 g/cm³ x 432 cm³ = 544.75 g

Converting to Kg:

544.75 g x 1 Kg/ 1000 g = 0.544 kg

Now the molality is

m = mol sucrose/ kg solvent = 3.24 x 10⁻³ mol / 0.544 Kg = 0.0060 m

Note: In the calculation for volume of solution we could have approximated it to that of just glycerine, but since the density of sucrose was given we calculated the total volume of solution to be more rigorous.

8 0

3 years ago