Answer:
MgCO₃
Explanation:
From the question given above, we obtained:
MgF₂ + Li₂CO₃ —> __ + 2LiF
The missing part of the equation can be obtained by writing the ionic equation for the reaction between MgF₂ and Li₂CO₃. This is illustrated below:
MgF₂ (aq) —> Mg²⁺ + 2F¯
Li₂CO₃ (aq) —> 2Li⁺ + CO₃²¯
MgF₂ + Li₂CO₃ —>
Mg²⁺ + 2F¯ + 2Li⁺ + CO₃²¯ —> Mg²⁺CO₃²¯ + 2Li⁺F¯
MgF₂ + Li₂CO₃ —> MgCO₃ + 2LiF
Now, we share compare the above equation with the one given in the question above to obtain the missing part. This is illustrated below:
MgF₂ + Li₂CO₃ —> __ + 2LiF
MgF₂ + Li₂CO₃ —> MgCO₃ + 2LiF
Therefore, the missing part of the equation is MgCO₃
Answer:
nickel, cobalt would decrease in size when it became an iron
Answer:
The answer to your question is P = 1.95 atm
Explanation:
Data
Pressure = P = ?
number of moles = n = 0.122
Volume = V = 1.5 l
Temperature = T = 20°C
Constant of ideal gases = 0.082 atm l/mol°K
Process
1.- Convert temperature to °K
T = 20 + 273
T = 293°K
2.- Write the formula of ideal gases
PV = nRT
-Solve for P
P = nRT/V
3.- Substitution
P = (0.122 x 0.082 x 293) / 1.5
4.- Simplification
P = 2.93 / 1.5
5.- Result
P = 1.95 atm
I believe your answer is Favorable.
Hope this helps, and happy studying~!
~{Dunsforhands}