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murzikaleks [220]
3 years ago
12

When you have an e-mail message to send to several people, where is the best place to find their e-mail addresses? the Bcc field

the From field the subject line the address book
Computers and Technology
2 answers:
Effectus [21]3 years ago
8 0

Answer:

i'd say "Address book"

Explanation:

stich3 [128]3 years ago
6 0

you can find them in the Bcc field if you have sent them an email before or if they are registered in you address book then they will be there as well

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What is the code for Pong that would work on Khan Academy?
Rashid [163]
Draw = function() {
if () {
if (keyCode === ){
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7 0
3 years ago
You are a visitor at a political convention with delegates; each delegate is a member of exactly one political party. It is impo
Fed [463]

Answer:

The algorithm is as follows:

Step 1: Start

Step 2: Parties = [All delegates in the party]

Step 3: Lent = Count(Parties)

Step 4: Individual = 0

Step 5: Index = 1

Step 6: For I in Lent:

Step 6.1: If Parties[Individual] == Parties[I]:

Step 6.1.1: Index = Index + 1

Step 6.2: Else:

Step 6.2.1 If Index == 0:

Step 6.2.2: Individual = I

Step 6.2.3: Index = 1

Step 7: Else

Step 7.1: Index = Index - 1

Step 8: Print(Party[Individual])

Step 9: Stop

Explanation:

The algorithm begins here

Step 1: Start

This gets the political parties as a list

Step 2: Parties = [All delegates in the party]

This counts the number of delegates i.e. the length of the list

Step 3: Lent = Count(Parties)

This initializes the first individual you come in contact with, to delegate 0 [list index begins from 0]

Step 4: Individual = 0

The next person on the list is set to index 1

Step 5: Index = 1

This begins an iteration

Step 6: For I in Lent:

If Parties[Individual] greets, shakes or smile to Party[i]

Step 6.1: If Parties[Individual] == Parties[I]:

Then they belong to the same party. Increment count by 1

Step 6.1.1: Index = Index + 1

If otherwise

Step 6.2: Else:

This checks if the first person is still in check

Step 6.2.1 If Index == 0:

If yes, the iteration is shifted up

Step 6.2.2: Individual = I

Step 6.2.3: Index = 1

If the first person is not being checked

Step 7: Else

The index is reduced by 1

Step 7.1: Index = Index - 1

This prints the highest occurrence party

Step 8: Print(Party[Individual])

This ends the algorithm

Step 9: Stop

The algorithm, implemented in Python is added as an attachment

<em>Because there is an iteration which performs repetitive operation, the algorithm running time is: O(n) </em>

Download txt
5 0
3 years ago
Consider the university enrollment database schema: 547 Student(snurn: integer, snarne: string, majoT: string, level: string, ag
trapecia [35]

Enroll a student identified by her snum into the class named 'Introduction to Database Systems' is the following transactions, state the SQL isolation level you would use.

1. Enroll a student identified by her snum into the class named 'Introduction to Database Systems'.

<u>Explanation:</u>

Since enroll is unique in the university enrollment database schema and field name is SNUM and it is data type is an integer. To identify student class name and department name and name of student SNUM field is used for searching in university enrollment database schema. Enrollment changing is not possible of the student’s not possible or not good practices in university enrollment database schema.

If a query had been made class wise or department wise enrollment is played an important role.

For  assign, a faculty is made on the class id or  department id.

8 0
4 years ago
A college team's BCS football ranking is comprised of three elements:1) the Harris Poll score, 2) the Coaches Poll score, and 3)
artcher [175]

Answer:

harris_poll_ranking = int(input("Enter team's Harris Poll ranking [1 - 2,850]: "))

coaches_poll_ranking = int(input("Enter team's Coaches Poll ranking [1 - 1,475]: "))

computer_ranking  = float(input("Enter team's computer ranking  [0 - 1]: "))

harris_poll_score = harris_poll_ranking / 2850

coaches_poll_score = coaches_poll_ranking / 1475

bcs_score = harris_poll_score / 3 + coaches_poll_score / 3 + computer_ranking / 3

print(bcs_score)

Explanation:

*The code is in Python.

Ask the user to enter the  harris_poll_ranking as int, coaches_poll_ranking as int and computer_ranking as float

Calculate the harris_poll_score, divide the harris_poll_ranking by 2850

Calculate the coaches_poll_score, divide the coaches_poll_ranking by 1475

Calculate the bcs_score, harris_poll_score, coaches_poll_score and computer_ranking by 3 and sum them

Print the bcs_score

6 0
4 years ago
Apart from the challenges of heterogeneity, business and social change and trust and security, identify other problems and chall
Klio2033 [76]

Answer:

The challenge of cost control

The challenge of competence

The challenge of reduced system delivery times.

Explanation:The Challenge of Cost control is a major challenge affecting the software engineering in the 21st century,the cost of Microchips and other hardware are constantly rising.

The challenge of competence is another major challenge affecting software engineering in the 21st century,as most software engineers lack the required competence to handle some of the issues facing softwares.

The challenge of reduced system delivery times is a major challenge likely to affect software engineering in the 21st century,as people required the software to be available in the shortest possible time.

7 0
3 years ago
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