Answer:
45.93°
Explanation:
The angle of incidence is given as 32.7°
The refractive index of the water that is ![n_1=1.33](https://tex.z-dn.net/?f=n_1%3D1.33)
Refractive index of the air that is
(because the refractive index of air is 1 )
We have to find the angle at which the light leave the water means angle of refraction
So according to snell's law ![n_1sini=n_2sinr](https://tex.z-dn.net/?f=n_1sini%3Dn_2sinr)
![1.33sin32.7=1\times sinr](https://tex.z-dn.net/?f=1.33sin32.7%3D1%5Ctimes%20sinr)
![sinr=0.7185](https://tex.z-dn.net/?f=sinr%3D0.7185)
r =45.93°
So the light leave the water at an angle of 45.93°
Answer:
A. Zero
Explanation:
The force on a coil of N turns, enclosing an area, A and carrying a current I in the presence of a magnetic field B, is :
F = N * I * A * B * sinθ
Where θ is the angle between the normal of the enclosed area and the magnetic field.
Since the normal of the area is parallel to the magnetic field, θ = 0
Hence:
F = NIABsin0
F = 0 or Zero
Thew energy stored in a capacitor of capacitance
and voltage between the plates
is
.
Substituting numerical value
![E=\frac{1}{2*6*10^{-6}} (40*10^{-6})^2\\ E=133.33\; \mu J](https://tex.z-dn.net/?f=%20E%3D%5Cfrac%7B1%7D%7B2%2A6%2A10%5E%7B-6%7D%7D%20%2840%2A10%5E%7B-6%7D%29%5E2%5C%5C%20E%3D133.33%5C%3B%20%5Cmu%20J%20)
I believe the best example of Newton's First Law of motion would be the example or illustration with the basketball player. An object will move in a straight line or a given direction at a constant speed unless or until another force acts upon the object, causing a change in speed and or direction.
Okay, haven't done physics in years, let's see if I remember this.
So Coulomb's Law states that
![F = k \frac{Q_1Q_2}{d^2}](https://tex.z-dn.net/?f=F%20%3D%20k%20%5Cfrac%7BQ_1Q_2%7D%7Bd%5E2%7D)
so if we double the charge on
![Q_1](https://tex.z-dn.net/?f=Q_1)
and double the distance to
![(2d)](https://tex.z-dn.net/?f=%282d%29)
we plug these into the equation to find
<span>
![F_{new} = k \frac{2Q_1Q_2}{(2d)^2}=k \frac{2Q_1Q_2}{4d^2} = \frac{2}{4} \cdot k \frac{Q_1Q_2}{d^2} = \frac{1}{2} \cdot F_{old}](https://tex.z-dn.net/?f=F_%7Bnew%7D%20%3D%20k%20%5Cfrac%7B2Q_1Q_2%7D%7B%282d%29%5E2%7D%3Dk%20%5Cfrac%7B2Q_1Q_2%7D%7B4d%5E2%7D%20%3D%20%5Cfrac%7B2%7D%7B4%7D%20%5Ccdot%20k%20%5Cfrac%7BQ_1Q_2%7D%7Bd%5E2%7D%20%3D%20%5Cfrac%7B1%7D%7B2%7D%20%5Ccdot%20F_%7Bold%7D)
</span>
So we see the new force is exactly 1/2 of the old force so your answer should be
![\frac{1}{2}F](https://tex.z-dn.net/?f=%5Cfrac%7B1%7D%7B2%7DF)
if I can remember my physics correctly.