The magnitude of a vertical electric field that will balance the weight of a plastic sphere of mass 2. 1 g that has been charged to -3. 0 NC is 6.86 ×
N/C.
An electric field is the physical field that surrounds electrically charged particles and exerts a force on all other charged particles in the field, either attracting or repelling them. It also refers to the physical field of a system of charged particles.
It is given that,
Mass of sphere, m = 2.1 g =0.0021kg
Charge,q = ₋3nC = ₋ 3 ₓ 
To balance the weight of a plastic sphere, we must determine the magnitude of the electric field. So,

a = g

E = 
E = 6860000 N/C
E = 6.86 ×
N/C
Hence, the magnitude of the electric field that balances its weight is 6.86 ×
N/C .
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That's false. If it had only magnitude it would be speed. Velocity also has Direction.
Chloroplasts and vacuoles
Answer:
λ = 0.905m
Explanation:
TThe wavelength (λ) only depends on the harmonic (n) and the length of the string (L):
λ = 2L/n
λ = 2*1.81m /4
λ = 0.905m
Answer:
The distance away the center of the earthquake is 1083.24 km.
Explanation:
Given that,
Speed of transverse wave = 9.1\ km/s
Speed of longitudinal wave = 5.7 km/s
Time = 71 sec
We need to calculate the distance of transverse wave
Using formula of distance

....(I)
The distance of longitudinal wave
....(II)
From the first equation

Put the value of t in equation (II)




Hence, The distance away the center of the earthquake is 1083.24 km.