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s344n2d4d5 [400]
3 years ago
9

What is 3,108 rounded to the nearest thousand

Mathematics
2 answers:
Aleksandr [31]3 years ago
5 0

Answer:

3,000

Step-by-step explanation:

If the question was about 3,500 it would be rounded to 4,000

If the question was about 2,499 it would be rounded to 2,000

If it is in between 3,449 and 2,500 then it would be rounded to 3,000 which 3,108 is

goblinko [34]3 years ago
4 0

Answer:

3100

Step-by-step explanation:

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nirvana33 [79]
If you need 150g of flour for 12 cakes, that means you need 12.5 g of flour per cake. So if you multiply that by 30 it gives you
375g of flour

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3 years ago
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1. Order the numbers from least to greatest. 66 V21, 5.38 3​
IrinaK [193]

Answer:

3, 5.38, 66, V21

Step-by-step explanation:

I assumed that V was the roman numeral V, which is equivalent to the number 5. I then multiplied 5 by 21 which is 105. If this is not the case and they simply wanted us to replace the v with a 5, then the answer would still be correct because 521 is greater than all the numbers in this set. Hope this helps.

7 0
3 years ago
Solve each of the following quadratic equations<br><br> 3x=0.5x^2<br><br><br> 0=5x^2-2x+6
UNO [17]

<u>Question 1</u>

<u />3x=0.5x^{2}\\\\6x=x^{2} \\ \\ x^{2}-6x=0 \\ \\ x(x-6)=0 \\ \\ \boxed{x=0, 6}

<u>Question 2</u>

<u />0=5x^{2}-2x+6 \\ \\ x=\frac{2 \pm \sqrt{(-2)^{2}-4(5)(6)}}{2} \\ \\ x=\frac{2 \pm \sqrt{-116}}{10} \\ \\ x=\frac{2 \pm 2i\sqrt{29}}{10} \\ \\ \boxed{x=\frac{1 \pm i\sqrt{29}}{5}}

6 0
2 years ago
The sum of two terms of gp is 6 and that of first four terms is 15/2.Find the sum of first six terms.​
Gnoma [55]

Given:

The sum of two terms of GP is 6 and that of first four terms is \dfrac{15}{2}.

To find:

The sum of first six terms.​

Solution:

We have,

S_2=6

S_4=\dfrac{15}{2}

Sum of first n terms of a GP is

S_n=\dfrac{a(1-r^n)}{1-r}              ...(i)

Putting n=2, we get

S_2=\dfrac{a(1-r^2)}{1-r}

6=\dfrac{a(1-r)(1+r)}{1-r}

6=a(1+r)                    ...(ii)

Putting n=4, we get

S_4=\dfrac{a(1-r^4)}{1-r}

\dfrac{15}{2}=\dfrac{a(1-r^2)(1+r^2)}{1-r}

\dfrac{15}{2}=\dfrac{a(1+r)(1-r)(1+r^2)}{1-r}

\dfrac{15}{2}=6(1+r^2)            (Using (ii))

Divide both sides by 6.

\dfrac{15}{12}=(1+r^2)

\dfrac{5}{4}-1=r^2

\dfrac{5-4}{4}=r^2

\dfrac{1}{4}=r^2

Taking square root on both sides, we get

\pm \sqrt{\dfrac{1}{4}}=r

\pm \dfrac{1}{2}=r

\pm 0.5=r

Case 1: If r is positive, then using (ii) we get

6=a(1+0.5)  

6=a(1.5)  

\dfrac{6}{1.5}=a  

4=a

The sum of first 6 terms is

S_6=\dfrac{4(1-(0.5)^6)}{(1-0.5)}

S_6=\dfrac{4(1-0.015625)}{0.5}

S_6=8(0.984375)

S_6=7.875

Case 2: If r is negative, then using (ii) we get

6=a(1-0.5)  

6=a(0.5)  

\dfrac{6}{0.5}=a  

12=a  

The sum of first 6 terms is

S_6=\dfrac{12(1-(-0.5)^6)}{(1+0.5)}

S_6=\dfrac{12(1-0.015625)}{1.5}

S_6=8(0.984375)

S_6=7.875

Therefore, the sum of the first six terms is 7.875.

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Find the value of x.<br> 43°<br> X<br> x = [?]°
ZanzabumX [31]
The opposite sides are supplementary
43+x=180
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