Question

Aluminum hydroxide is often present in antacids to neutralize stomach acid (HCl). If 14.0 g aluminum hydroxide is present in an antacid tablet, determine the theoretical yield of aluminum chloride produced when the tablet reacts with stomach acid. If the actual yield of the aluminum chloride from this tablet is 22.0 g, what is the percent yield?

Answer 1

Answer:

Percent Yield = 91.97%

Explanation:

Aluminum hydroxide Formula: Al(OH)3 Molar mass: 78 g/mol

Stomach acid Formula: HCl Molar mass: 36.46 g/mol

Aluminum Chloride Formula: AlCl₃ Molar mass: 133.34 g/mol

14g Al(OH)3

2Al(OH)3 + Cl2 → 2Al(OH)3Cl

Balanced equation

14/156 = 0.0897 Moles of Al(OH)3

Ratio is 2:1:2 so same ratio for Al(OH)3 to AlCl₃

0.0897 x 266.68 = 23.92grams of AlCl₃

Theoretical yield of aluminum chloride

Actual yield aluminum chloride 22.0 g

Percent yield?

Percent Yield = (actual Yield/Theoretical yield) x 100

Percent Yield = (22/23.92) x 100

Percent Yield = 91.97%