Is baking powder Litmus acid or base
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Answer : The heat released by the combustion of 1.121 mol of hexane (kJ) is,
Explanation :
The given balanced reaction is,
Given:
Moles of hexane = 0.121 mol
= -8326 kJ/mol
The negative sign indicate that the reaction exothermic or amount of heat released.
As, 1 mole of hexane released heat = 8326 kJ
So, 0.121 mole of hexane released heat = 8326 × 0.121 = 1007.446 ≈
Therefore, the heat released by the combustion of 1.121 mol of hexane is .
Taking into account the definition of calorimetry ans sensible heat, you need a heat of 38.72 kJ to raise the temperature of 400 g of ethanol from 20 °C to 60 °C.
<h3>What is calorimetry and sensible heat</h3>Calorimetry is the measurement and calculation of the amounts of heat exchanged by a body or a system.
Sensible heat is defined as the amount of heat that a body absorbs or releases without any changes in its physical state (phase change).
So, the equation that allows to calculate heat exchanges is:
Q = c× m× ΔT
where
- Q is the heat exchanged by a body of mass m.
- c is the specific heat substance c.
- ΔT is the temperature variation.
In this case, you know:
- Q= ?
- c= 2.42
- m= 400 g
- ΔT= Tfinal - Tinitial= 60 °C - 20 °C= 40 °C
Replacing in the definition of sensible hear:
Q = 2.42 × 400 g× 40 °C
Solving:
<u><em>Q= 38,720 J= 38.72 kJ</em></u>
Finally, you need a heat of 38.72 kJ to raise the temperature of 400 g of ethanol from 20 °C to 60 °C.
Learn more about sensible heat:
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