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Zanzabum
3 years ago
14

Urea is a product of digestion of proteins and other foods that contain nitrogen. It can react with water and acid to form ammon

ium ions and bicarbonate ions according to the equation below: (upper N upper h subscript 2) subscript 2 upper C upper O (a q) plus 2 upper h subscript 2 upper o (l) plus upper H superscript plus (a q) right arrow 2 upper N upper H subscript 4 superscript plus (a q) plus upper h upper C upper O subscript 3 superscript minus (a q). The enzyme urease catalyzes this reaction. If urease is added to a solution that contains ammonia and other nitrogen-containing compounds (but no urea), will the urease catalyze any reactions? Explain your answer.
Chemistry
2 answers:
irina [24]3 years ago
7 0

Answer:

The urease will not catalyze any reaction.

Explanation:

The hydrolysis reaction of urea is:

(NH₂)₂CO + 2 H₂O + H⁺ ⇒ 2 NH₄⁺ + HCO₃⁻

Urease is an enzyme that catalyzes the urea hydrolysis reaction. Enzymes are very specific referring to the substrates they catalyze. If the solution does not contain urea, the urease will not bind to any of the substances in the solution, so it will not catalyze any reaction in the solution.

maw [93]3 years ago
7 0

Answer:

Urease is an enzyme.

Enzymes are highly specific in the reactions they catalyze.

Enzymes can typically bind only to the substrate(s) for the reaction they catalyze.

If the solution contains no urea, urease will not bind to any of the substances in the solution, so it will not catalyze any reactions in the solution.

Explanation:

Those are the answers.

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Find the concentration of H+ ions at a pH = 11 and
Black_prince [1.1K]

Explanation:

the pH of the solution defined as negatuve logarithm of H^+ ion concentration.

pH=-\log[H^+]

1. Hydrogen ion concentration when pH of the solution is 11.

11=-\log[H^+]

[H^+]=1\times 10^{-11} mol/L..(1)

At pH = 11, the concentration of H^+ ions is 1\times 10^{-11} mol/L.

2. Hydrogen ion concentration when the pH of the solution is 6.

6=-\log[H^+]'

[H^+]'=1\times 10^{-6} mol/L..(2)

At pH = 6, the concentration of H^+ ions is 1\times 10^{-6} mol/L.

3. On dividing (1) by (2).

\frac{[H^+]}{[H^+]'}=\frac{1\times 10^{-11} mol/L}{1\times 10^{-6} mol/L}=1\times 10^{-5}

The ratio of hydrogen ions in solution of pH equal to 11 to the solution of pH equal to 6 is 1\times 10^{-5}.

4. Difference between the H^+ ions at both pH:

1\times 10^{-6} mol/L-1\times 10^{-11} mol/L=9.99\time 10^{-7} mol/L

This means that Hydrogen ions in a solution at pH = 7 has 9.99\time 10^{-7} mol/L ions fewer than in a solution at a pH = 6

6 0
3 years ago
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What is the percentage strength (w/w) of a solution made by dissolving 62.5 g of potassium chloride in 187.5 ml of water?
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Given data:

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We know that the density of water = 1 g/ml

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We have a solution of 62.5 g of potassium chloride in 187.5 g water

Therefore, amount of solute in 100 g of water= 62.5 * 100/187.5 = 33.33

The percentage strength = 33.33 %

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3 years ago
How many significant figures are in 4.8cm?
kramer

Answer: 2. they are 4 and 8

Explanation: I took the exam. I hope I helped :)

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3 years ago
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