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Wewaii [24]
3 years ago
15

Cadmium bromide is used in photography and lithography. What is the molality of a solution prepared by dissolving 45.38 g of CdB

r2 in 375.0 g of water?
Chemistry
1 answer:
mash [69]3 years ago
6 0

Answer:

0.44 m is the molality

Explanation:

Molality means mol of solute in 1kg of solvent.

Solute → CdBr₂

Solvent → H₂O

Mass / Molar mass = 45.38 g / 272.21 g/m = 0.167 moles

1 g = 1x10⁻³ kg

375 g = 0.375 kg

0.167 m/0.375 kg = 0.44 m

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How much water (H2O ) would form if 4.04 g of hydrogen (H2) reacted with 31.98 g of oxygen (O2 )?
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Answer:

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Explanation:

Given data:

Mass of water formed = ?

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Solution:

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Now we will compare the moles of water with hydrogen and oxygen.

                O₂         :         H₂O

                 1           :           2

                H₂         :         H₂O

                 2          :          2

               2.02       :      2.02

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Mass = 2 mol × 18 g/mol

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