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stich3 [128]
3 years ago
5

hich quantity describes how spread out a set of data is? O A. Standard deviation O B. Percent error O C. Line of best fit D. Mea

n
Chemistry
1 answer:
juin [17]3 years ago
6 0

The answer to this is B.

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The ratio of carbon atoms to hydrogen atoms to oxygen atoms in a molecule of dicyclohexyl maleate is 4 to 6 to 1. what is its mo
Semenov [28]
Knowing the ratio between atoms we can write an empirical formula: 

<span>C4H6O </span>

<span>we compute the molar mass of this single formula: </span>
<span>4x12 + 6 x 1 + 16 x1 = 70 g / mol </span>

<span>Now, as we know the actual molar mas being 280 g/mol, we divide this number by 70 and we get the ratio between empirical formula and molecular actual formula: </span>

<span>280 / 70 = 4 </span>

<span>This means that actual molecular formula is: </span>

<span>(C4H6O)4 or </span>

<span>C16H24O4 </span>
3 0
3 years ago
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The black fur absorbs all the colors where the white fun reflects all the colors because we see the green grass it absorbs all the colors except green and the yellow dandelion is reflecting yellow and orange because it’s color is like a mix of them but it still absorbs the other colors
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3 years ago
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A given mass of air has a volume of 8.00 L at 60.0°C. At constant pressure, the temperature is increased to 80.0°C. Calculate th
AleksandrR [38]

Answer:

D. 6.00 L

Explanation:

What we have here is an example of Boyle's Law. The equation here is P₁ · V₁ = P₂ · V₂. We know all of the values except for V₂.

60(8) = 80V

<em>Multiply 60 by 8 to get 480.</em>

480 = 80V

<em>Divide both sides by 80.</em>

480/80 = V

6 = V

The final volume for the gas is 6.00 L.

5 0
2 years ago
The reaction of hydrogen and iodine to produce hydrogen iodide has a Kc of 54.3 at 703 K. Given the initial concentrations of H2
pentagon [3]

Answer:

[HI] = 0.7126 M

Explanation:

Step 1: Data given

Kc = 54.3

Temperature = 703 K

Initial concentration of H2 and I2 = 0.453 M

Step 2: the balanced equation

H2 + I2 ⇆ 2HI

Step 3: The initial concentration

[H2] = 0.453 M

[I2] = 0.453 M

[HI] = 0 M

Step 4: The concentration at equilibrium

[H2] = 0.453 - X

[I2] = 0.453 - X

[HI] = 2X

Step 5: Calculate Kc

Kc = [Hi]² / [H2][I2]

54.3 = 4x² / (0.453 - X(0.453-X)

X = 0.3563

[H2] = 0.453 - 0.3563 = 0.0967 M

[I2] = 0.453 - 0.3563 = 0.0967 M

[HI] = 2X = 2*0.3563 = 0.7126 M

3 0
3 years ago
Which of the following is a combustion reaction?
Rina8888 [55]
The answer is b it is a combustion reaction
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3 years ago
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