Sodium-22 remain : 1.13 g
<h3>Further explanation
</h3>
The atomic nucleus can experience decay into 2 particles or more due to the instability of its atomic nucleus.
Usually, radioactive elements have an unstable atomic nucleus.
General formulas used in decay:
T = duration of decay
t 1/2 = half-life
N₀ = the number of initial radioactive atoms
Nt = the number of radioactive atoms left after decaying during T time
half-life = t 1/2=2.6 years
T=15.6 years
No=72.5 g
Answer:
95.211 g/mol
Explanation:
For example magensium chloride has the formula unit MgCl2 , i..e., for every magnesium cation there are two chloride anions in the crystal. Or, we would say that the formula weight of MgCl2 = 95.211 g/mol.
Forces can be added only when they both are going in the same direction as 2n +2n = 4n of force in the same direction if they are 2 facing forces they would <span>have had to be subtracted, which ever force is greater that will be the momentum of the force.
Hope this helps.</span>
Answer:
c = 0.9 j/g. °C
Explanation:
Given data:
Mass of aluminium = 100 g
Initial temperature = 90 °C
Final temperature = 20°C
Heat transfer = 6300 J
Specific heat of aluminium = ?
Solution:
Formula:
Q = m.c. ΔT
Q = amount of heat absorbed or released
m = mass of given substance
c = specific heat capacity of substance
ΔT = change in temperature
The Q will negative because metal release the heat.
c = Q / m. ΔT
ΔT = t2 - t1
ΔT = 20°C - 90 °C
ΔT = -70 °C
c = -6300 j/ 100 g.-70°C
c = -6300 j/ -7000 g.°C
c = 0.9 j/g. °C
Answer:
P^3- > S^2- > Cl^- > K^+ > Sc^3+
Explanation:
Ionic radii is an example of physical properties of Periodicity.
The size of an atom's ion is difficult to estimate because of the electronic distribution and arrangement. This is due to the fact that the atom' ion have no definite outer boundary. In order to circumvent this problem, the atom's ion is estimated in a crystal lattice in terms of its ionic radii.
Ionic radii is taken as half the distance between atomic ions in a crystal lattice. Across a period in the periodic table , ionic radii decreases progressively from left to right.
Down the group, the ionic radius increases from top to bottom.
So the arrangement of the given elements from largest to smallest radius in the decreasing order of ionic radius will be:
P^3- > S^2- > Cl^- > K^+ > Sc^3+
