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3 years ago

If you start with 4.3 moles of NH3, how many moles of NANH2 can be produced

Chemistry

1 answer:

mash [69]3 years ago

4 0

Explanation:

Mole ratio of NH3 to NaNH2 = 2 : 2.

Moles of NaNH2 produced

= 4.3mol * (2/2) = 4.3mol.

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The Kp for the reaction below is 1.49 × 108 at 100.0°C:CO(g) + Cl2(g) → COCl2(g)In an equilibrium mixture of the three gases, PC

Serggg [28]

<u>Answer:</u> The equilibrium partial pressure of phosgene is 7.34 atm

<u>Explanation:</u>

The given chemical equation follows:

$CO(g)+Cl_2(g)\rightleftharpoons COCl_2(g)$

The expression of $K_p$ for above equation follows:

$K_p=\frac{p_{COCl_2}}{(p_{CO})\times (p_{Cl_2})}$

We are given:

Equilibrium partial pressure of CO = $2.22\times 10^{-4}atm$

Equilibrium partial pressure of chlorine gas = $2.22\times 10^{-4}atm$

$K_p=1.49\times 10^8$

Putting values in above equation, we get:

$1.49\times 10^8=\frac{p_{COCl_2}}{(2.22\times 10^{-4})\times (2.22\times 10^{-4})}\\\\p_{COCl_2}=7.34atm$

Hence, the equilibrium partial pressure of phosgene is 7.34 atm

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3 years ago

How many electrons are transferred between the cation and anion to form the ionic bond in one formula unit of each compound?

Aliun [14]

Answer:

1, 2, 1, 1, 2

Explanation:

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3 years ago

How much heat (in kJ) would need to be removed to cool 150.3 g of water from 25.60°C to -10.70°C?

olga_2 [115]

Answer:

Q = -22.9 kJ

Explanation:

Given that,

Mass of water, m = 150.3 g

Water gets cool from 25.60°C to -10.70°C.

The specific heat of water, c = 4.2 J/g°C

The formula for heat needed is given by :

$Q=mc\Delta T\\\\Q=150.3\times 4.2 \times (-10.7-25.6)\\\\Q=-22914.738\\\\or\\\\Q=22.9\ kJ$

So, 22.9 kJ of heat is needed to be removed to cool.

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3 years ago

The drawing shows a chemical reaction between hydroxide and bromomethane to produce methanol and bromide ion. The middle drawing

Dafna11 [192]

Answer:

Explanation:

Exothermic means the energy of products is lower than energy of reactants. Transition state will always be the highest energy among the two.

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IRINA_888 [86]

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3 years ago