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3 years ago

If you start with 4.3 moles of NH3, how many moles of NANH2 can be produced

Chemistry

1 answer:

mash [69]3 years ago

4 0

Explanation:

Mole ratio of NH3 to NaNH2 = 2 : 2.

Moles of NaNH2 produced

= 4.3mol * (2/2) = 4.3mol.

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Susana heats up a sample of red crystals. While the sample is being heated, a gas is released and a blue powder is left after th

frutty [35]

Answer: Compound

Explanation:

Element is a pure substance which is composed of atoms of similar elements.It can not be decomposed into simpler constituents using chemical reactions.Example: Copper $Cu$

Compound is a pure substance which is made from atoms of different elements combined together in a fixed ratio by mass.It can be decomposed into simpler constituents using chemical reactions. Example: water $H_2O$

$2H_2O\rightarrow 2H_2+O_2$

Thus as it give that the red sample on being heated, a gas is released and a blue powder is left after the heating. Thus the given sample is a compound.

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An empty plastic bottle is sealed in a cool room and then moved to a very hot room. What can best be stated about the air pressu

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<span>It is higher than the pressure on the outside of the bottle.</span>

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3 years ago

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NO GUESSING!ONLY RIGHT ANSWER

lutik1710 [3]

<h3> <u>ANSWER</u></h3>

2. Neon, only

<h3><u>EXPLANATION</u></h3>

When Na and F combine they form an electron configuration of 2-8. Na electron configuration is 2-8-1 while F is 2-7, so when they form an ionic bond F will gain Na outermost electron to complete its valence shell due to having a higher negativity. Neon has an electron configuration of 2-8 but argon has 2-8-8.

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3 years ago

Which statement correctly describes metallic bonds?

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Answer: D

Explanation:

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3 years ago

You have 2.2 mol Xe and 2.0 mol F₂, but when you carry out the reaction you end up with only 0.25 mol XeF₄. What is the percent

alexira [117]

Answer:

The correct answer is 25 %

Explanation:

According to the chemical reaction:

Xe(g) + 2 F₂ (g) → XeF₄ (g)

1 mol of Xe(g) reacts with 2 mol of F₂(g), so the stoichiometric ratio os reactants is 2 mol F₂/mol Xe.

We have 2.2 mol Xe and 2.0 mol F₂, so the ratio is:

2.0 mol F₂/2.2 mol Xe = 0.909 mol F₂/mol Xe

The molar ratio of reactant we have is lower than the required, so F₂ is the limiting reactant.

By using the limiting reactant, we calculate the theoretical amount of product (XeF₄). For this, we know that 1 mol of XeF₄ is formed from 2 mol of F₂ (1 mol XeF₄/ 2 mol F₂), and we have 2.0 mol F₂:

2.0 mol F₂ x (1 mol XeF₄/ 2 mol F₂)= 1 mol XeF₄

If we only obtained 0.25 mol XeF₄, the percent yield of the experiment is:

Yield = experimental amount/theoretical amount x 100%

= 0.25 mol XeF₄/ 1 mol XeF₄ x 100% = 25 %

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3 years ago