Answer:
Step-by-step explanation:
Represent the length of one side of the base be s and the height by h. Then the volume of the box is V = s^2*h; this is to be maximized.
The constraints are as follows: 2s + h = 114 in. Solving for h, we get 114 - 2s = h.
Substituting 114 - 2s for h in the volume formula, we obtain:
V = s^2*(114 - 2s), or V = 114s^2 - 2s^3, or V = 2*(s^2)(57 - s)
This is to be maximized. To accomplish this, find the first derivative of this formula for V, set the result equal to 0 and solve for s:
dV
----- = 2[(s^2)(-1) + (57 - s)(2s)] = 0 = 2s^2(-1) + 114s - 2s^2
ds
Simplifying this, we get dV/ds = -4s^2 + 114s = 0. Then either s = 28.5 or s = 0.
Then the area of the base is 28.5^2 in^2 and the height is 114 - 2(28.5) = 57 in
and the volume is V = s^2(h) = 46,298.25 in^3
Answer:
ITS "B"
Step-by-step explanation:
The answer is A because 24 3/8 inches is roughly 2 feet, 100/2 is 50, and since there is a small 3/8 value, the answer is 49
Answer: R2280
Step-by-step explanation:
Total crates = 10
Bottles in one crate = 12
Total bottles = 10 x 12 = 120
Price of 1 bottle = R19
Price of 120 bottles = R19 x 120 = R2280
Answer:
300
Step-by-step explanation:
27% = 81
1% = 81/27 = 3
100% = 100x3 = 300people
