Answer:
The strength of a bond between two atoms increases as the number of electron pairs in the bond increases.
Explanation:
Answer:
6.4 × 10^-10 M
Explanation:
The molar solubility of the ions in a compound can be calculated from the Ksp (solubility constant).
CaF2 will dissociate as follows:
CaF2 ⇌Ca2+ + 2F-
1 mole of Calcium ion (x)
2 moles of fluorine ion (2x)
NaF will also dissociate as follows:
NaF ⇌ Na+ + F-
Where Na+ = 0.25M
F- = 0.25M
The total concentration of fluoride ion in the solution is (2x + 0.25M), however, due to common ion effect i.e. 2x<0.25, 2x can be neglected. This means that concentration of fluoride ion will be 0.25M
Ksp = {Ca2+}{F-}^2
Ksp = {x}{0.25}^2
4.0 × 10^-11 = 0.25^2 × x
4.0 × 10^-11 = 0.0625x
x = 4.0 × 10^-11 ÷ 6.25 × 10^-2
x = 4/6.25 × 10^ (-11+2)
x = 0.64 × 10^-9
x = 6.4 × 10^-10
Therefore, the molar solubility of CaF2 in NaF solution is 6.4 × 10^-10M
Reduction involves the either the addition of hydrogen and removal of oxygen.
<h3>What is reduction?</h3>
Reduction involves the removal of oxygen.
This implies there is a loss of oxygen in reduction.
This can be represented in the extraction of iron from it ores.
Fe₂O₃ + 3CO → 2Fe + 3CO₂
Reduction is also the addition of hydrogen. This implies it is the gain of hydrogen.
For example
CH₃CHO → CH₃CH₂OH
learn more on reduction here: brainly.com/question/9485345
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Answer:
the ionic radius of the anion 
Explanation:
From the diagram shown below :
The anion 
is located at the corners
The cation 
is located at the body center
The Body diagonal length = 
∴ 
Given that :
(i.e the ratio of the ionic radius of the cation to the ionic radius of
the anion )
Also ; a = 664 pm
Then :
Therefore, the ionic radius of the anion
Complete Question:
The complete question is on the first uploaded image
Answer:
The solution is on the second uploaded image
Explanation:
The explanation of the above solution is on the third uploaded image.
