What is the 24th term of the arithmetic sequence where a1 = 8 and a9 = 56?
1 answer:
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The given equation is equivalent to the expression -3c.
Given that, the expression can be written as.
By simplifying the above equation,
By taking out the common terms from the equation,
By simplifying the above equation by cancel out the common factors.
Now, by taking (-1) common from (-2c+1) we get,
By simplifying the above equation, we get the expression,
So the given equation is equivalent to the expression -3c.
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Answer:
Step-by-step explanation:
We khow that the equation of a circle is written this way :
(x-a)²+(y-b)²=r² where (x,y) are the coordinates of the cercle's points and (a,b) the coordinates of the cercle's center and r the radius .
Our task is to khow the values of a and b :
- We khow that the center is lying on the line 3x+2y=16⇒ 2y=-3x+16⇒ y=
x+8
- We khow that the points P and Q are two points in the cercle
- Let Ω be the center of this cercle
- we can notice that : PΩ AND QΩ are both equal to the radius ⇒ PΩ=QΩ= r
- So let's write the expression of this distance using vectors KHOWING THAT Ω(a,b)
- Vector PΩ(a-4,b-6) and Vector QΩ(a-8,b-2)
- PΩ=
and QΩ=
- Let's substitute a by x and b by y
- PΩ=QΩ we substitute each distance by its expression
- After simplyfying the expressions we get finally : -12+8x-8y=0
- now we have -12x +8x-8y=0 and the line equation 3x+2y-16=0
- these are simultanious equations so after solving them we get x=3.8 wich is approximatively 4 and y=2
- we substitute a by 4 and y by 2 in PΩ to get the radius
- we get r =
= 4
- so r²= 16
- then the equation is : (x-4)²+(y-2)²=16