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Lesechka [4]
4 years ago
11

1. Anthony walks to the pizza place for lunch. He walks 1km east then 1km south east again.

Chemistry
2 answers:
TiliK225 [7]4 years ago
8 0
The answer is: distance is 3 km, displacement is 2.24 km.

Distance is total length: 1 km east + 1 km south + 1 km east again = 3 km
Displacement is the hypotenuse of the right triangles which sides are 1 km east and 2 km south. According to the Pythagorean theorem:
a² + b² = c²
1² + 2² = c²
1 + 4 = c²
5 = c²
c = √5
c = 2.24 km
Ostrovityanka [42]4 years ago
5 0

Answer:

distance- 3 km

displacement- 2.24 km

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LenaWriter [7]
Presumptive tests, also known as preliminary tests or field tests, allow drugs to be quickly classified into a particular chemical group, but do not unequivocally identify the presence of a specific chemical compound.
4 0
3 years ago
HELP!!!! The freezing of methane is an exothermic change. What best describes the temperature conditions that are likely to make
vazorg [7]

<u>Answer:</u> The correct statement is low temperature only, because entropy decreases during freezing.

<u>Explanation:</u>

The relationship between Gibb's free energy, enthalpy, entropy and temperature is given by the equation:

\Delta G=\Delta H-T\Delta S

Where,

\Delta G = change in Gibb's free energy

\Delta H = change in enthalpy

T = temperature

\Delta S = change in entropy

It is given that freezing of methane is taking place, which means that entropy is decreasing and Delta S is becoming negative. It is also given that the reaction is an exothermic reaction, this means that the \Delta H is also negative.

For a reaction to be spontaneous, \Delta G must be negative.

-ve=-ve-[T(-ve)]\\\\-ve=-ve+T

From above equations, it is visible that \Delta G will be negative only when the temperature will be low.

Hence, the correct statement is low temperature only, because entropy decreases during freezing.

8 0
3 years ago
The equilibrium constant for the reaction 2NO2(g) N2O4(g) is Keq = . If a sample at equilibrium was found to contain 0.058 M NO2
Sladkaya [172]

Answer:

\boxed{3.6}

Explanation:

                  2NO₂ ⇌ N₂O₄

E/mol·L⁻¹:   0.058     0.012

K_{\text{eq}} = \dfrac{\text{[N$_{2}$O$_{4}$]}}{\text{[NO$_{2}$]$^{2}$}} = \dfrac{0.012}{0.058^{2}} = \mathbf{3.6} \\\\

\text{The $K_{\text{eq}}$ value would be $\boxed{\mathbf{3.6}}$}

7 0
4 years ago
A(n) _____________ is a mixture of fuel and oxygen for which the masses of these two components are exactly those needed for com
aev [14]

A stoichiometric mixture is a mixture of fuel and oxygen for which the masses of these two components are exactly those needed for complete combustion.

A stoichiometric mixture is a balanced mixture of fuel and oxygen.

The fuel and the oxygen react completely without the excesses of either.

The opposite of a stoichiometric mixture is called feeding an excess, when minimum one reactant is an excess amount.

Balanced chemical equation for reaction of combustion one type of a fuel: C₈H₁₈ + 25/2O₂ → 8CO₂ + 9H₂O

Stoichiometric mixture for this example is when fuel (C₈H₁₈) and oxygen(O₂) react in proportion 1 : 12.5.

More about a stoichiometric mixture: brainly.com/question/19585982

#SPJ4

6 0
2 years ago
Pleaseeeeee help with this i dont get it at all
Furkat [3]
Answer is C. in a reaction mole stays the same but mass changes and since it produced gas it means now we have less mass.
3 0
3 years ago
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