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sveticcg [70]
3 years ago
14

No links pls it’s very unhelpful

Chemistry
1 answer:
Reptile [31]3 years ago
7 0

answer : i don’t knowww :)

Right spelling:

Answer: I don’t know. :)

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What best describes the goals of scientific investigation and technological development?
bekas [8.4K]
Hi! I think the answer is option B. I hope
this helps, Goodluck :)
5 0
3 years ago
A bob of mass of 0.18 kilograms is released from a height of 45 meters above the ground level. What is the value of the kinetic
Drupady [299]

We can assume that all<span> gravitational potential energy is converted into kinetic energy of the object.</span><span>

<span>Hence, </span>GPE = KE

Where GPE is gravitational Potential Energy (J) and KE is Kinetic Energy (J)

GPE = mgh

<span>Where, m is the mass of the object (kg), g is acceleration due to gravity (9.8 m s</span></span>⁻<span>²) and h is the height to the<span> object from ground (m).</span></span><span>

m = 0.18 kg
g = 9.8 m s</span>⁻²<span>
h = 45 m

Hence, 
       GPE = 0.18 kg x 9.8 m s</span>⁻² x 45 m<span>
                = 79.38 J
                ≈ 79 J

<span>Hence, </span>KE = GPE = 79 J

<span>Hence, the answer is '79 joules'.</span></span>

8 0
3 years ago
Se disuelven 10 g de acido carbónico H2CO3 en 150 g de agua. Determina la concentración % m/m de esa disolución?
sergey [27]

The question is: 10 g of carbonic acid H2CO3 are dissolved in 150 g of water. Determine the% m / m concentration of that solution?

Answer: The% m / m concentration of that solution is 6.66%.

Explanation:

Given: Mass of solute = 10 g

Mass of solvent = 150 g

Formula used to calculate the %m/m is as follows.

Percent (m/m) = \frac{mass of solute}{mass of solvent} \times 100

Substitute the values into above formula as follows.

Percent (m/m) = \frac{mass of solute}{mass of solvent} \times 100\\= \frac{10 g}{150 g} \times 100\\= 6.66%

Thus, we can conclude that the% m / m concentration of that solution is 6.66%.

6 0
3 years ago
The molecule shown here can decolourise bromine water (above)
Sedaia [141]

Answer:

B hopefully this helps you

3 0
3 years ago
Imagine if during the cathode ray experiment, the size of the particles of the ray was the same as the size of the atom forming
Yakvenalex [24]

Answer:

This would support Dalton's postulates that proposed the atoms are indivisible because no small particles are involved.

Explanation:

Experiment using the gas discharge tube by J.J Thomson led to the discovery of cathode rays which are now known as electrons.

Primarily, Thomson's experiment led to the discovery of cathode rays, electrons, as subatomic particles.

If the size of the atoms observed at the cathode is the same as that of the rays,we can conclude that the particles of the rays are the simplest form of matter we can have. This would suggest that the atom is indeed the smallest indivisible particle of a matter according to Dalton.

7 0
4 years ago
Read 2 more answers
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