The given question is incomplete. The complete question is :
Gaseous butane reacts with gaseous oxygen gas to produce gaseous carbon dioxide and gaseous water . If 1.31g of water is produced from the reaction of 4.65g of butane and 10.8g of oxygen gas, calculate the percent yield of water. Be sure your answer has the correct number of significant digits in it.
Answer: 28.0 %
Explanation:
To calculate the moles :
According to stoichiometry :
13 moles of require 2 moles of butane
Thus 0.34 moles of will require= of butane
Thus is the limiting reagent as it limits the formation of product and butane is the excess reagent.
As 13 moles of give = 10 moles of
Thus 0.34 moles of give = of
Mass of
The percent yield of water is 28.0 %
Answer:
Acid is a molecule capable of donating hydrogen ion and they form aqueous solutions with a sour taste while base is a substance that accepts proton from proton donor and in aqueous solution, they have an astringent or bitter taste. Moreover, a good example for base is sodium hydrogen carbonate as baking soda or baking powder and for acid, the most common example is the acetic acid or vinegar.
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Answer:
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Answer:
. The old camera flash bulb used Mg metal sealed in a bulb with oxygen. At 25°C, the reaction is: Mg(s) + O2(a) → MgOS) AS (J/K.mol): Mg=32.7; O2=205.0; MgO=26.9 AH (kJ/mol: Mg=0; O2=0; MgO=-601.2
Explanation:
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