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Black_prince [1.1K]
4 years ago
10

Where would you most likely find transform boundaries on an earthquake distribution map?

Biology
2 answers:
lana66690 [7]4 years ago
5 0

Answer:

1st One

Explanation:

The distribution of earthquakes across the globe is shown in Figure 11.7. It is relatively easy to see the relationships between earthquakes and the plate boundaries. Along divergent boundaries like the mid-Atlantic ridge and the East Pacific Rise, earthquakes are common, but restricted to a narrow zone close to the ridge, and consistently at less than 30 km depth. Shallow earthquakes are also common along transform faults, such as the San Andreas Fault. Along subduction zones, as we saw in Chapter 10, earthquakes are very abundant, and they are increasingly deep on the landward side of the subduction zone

Damm [24]4 years ago
4 0
The answer is where earthquakes are deep and powerful. this is as earthquakes are usually much more frequent and powerful at fault lines. transform boundaries are 2 plates rubbing against each other thus creating earthquakes
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The count in a bacteria culture was 100 after 20 minutes and 2000 after 40 minutes. Assuming the count grows exponentially, What
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At t = 40 minutes, X = 2000

Substituting that into the formula

(i) ...    100 = Xo e^{k20}

(ii) ...    2000 = Xoe^{k40}

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\frac{2000}{100} = \frac{Xoe^{40k} } {Xoe^{20k}}

20 = e^{40k-20k} = e^{20k}

<em>[Xo cancels Xo. Division of values raised to a power is done by subtracting their powers]</em>

<em>Take the natural log of both sides</em>

㏑20 = 20k

<em>[taking the ㏑ cancels the exponential]</em>

k = \frac{ln20}{20}

<em>We can now substitute k to solve one of the equations</em>

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2000 = Xo e^{0.15*40}

2000 = Xo e^{6}

<em>Making Xo the subject of the formula</em>

Xo = \frac{2000}{e^{6} }

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THE DOUBLING TIME

The doubling time is the time it takes for the population to double, so 5 cells become 10 cells

Since Xo = 5

Given that X = Xo e^{kt}

When X=10,

10 = 5 e^{0.15t}

<em>solving for t:</em>

e^{0.15t} = \frac{10}{5}

Take ln of both sides

0.15t = ln 2

t =\frac{ln2}{0.15}

t =4.62 minutes

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X = 5 e^{0.15*65}

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WHEN WILL THE POPULATION REACH 12000

12000 = 5 e^{0.15t}

e^{0.15t} =240

take ln of both sides

0.15t = ln 2400

t = 51.89 minutes (approximately 52 minutes)

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