Answer:
y=log3(9x)
3^y = 9x
Step-by-step explanation:
Like of segment being r, calculated in the picture is the length
Answer:
To reconcile we need to match the checkbook balance with that of the bank balance :
Checkbook balance :
Initial checkbook balance = $43676.09
Note collected = $2160.00 , Bank Service Charge = $15
Final Checkbook Balance = Initial balance + Note collected - Service charge
= 43676.09 + 2160 - 15
= $45821.09
Bank balance :
Initial Bank balance = $49668.90
Outstanding deposits = $8474.44 , Outstanding checks = $12322.25
Final Bank Balance = Initial balance - Outstanding checks + Outstanding deposits
= 49668.90 - 12322.25 + 8474.44
= $45821.09
So, both the checkbook balance and the bank balance are equal.
Answer:
The longest braking distance one of these cars could have and still be in the bottom 1% is of 116.94 feet.
Step-by-step explanation:
Normal Probability Distribution:
Problems of normal distributions can be solved using the z-score formula.
In a set with mean
and standard deviation
, the z-score of a measure X is given by:

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the p-value, we get the probability that the value of the measure is greater than X.
The braking distances of a sample of cars are normally distributed, with a mean of 129 feet and a standard deviation of 5.18 feet.
This means that 
What is the longest braking distance one of these cars could have and still be in the bottom 1%?
This is the 1st percentile, which is X when Z has a pvalue of 0.01, so X when Z = -2.327.




The longest braking distance one of these cars could have and still be in the bottom 1% is of 116.94 feet.