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3 years ago

What is the molar mass for 5 mol Na

Chemistry

2 answers:

katrin [286]3 years ago

7 0

Answer:

molecular mass if Na

=2×23×12+3×16

=46+12+48

=106

no.of mole =

molecular wt.

Given wt.

106

wt=s30

Explanation:

zimovet [89]3 years ago

4 0

Answer:

22.98977 g/

Brainliest please

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2 years ago

Given that a chlorine-oxygen bond has an enthalpy of 243 kJ/mol , an oxygen-oxygen bond has an enthalpy of 498 kJ/mol , and the

Alecsey [184]

Explanation:

The chemical equation is as follows.

$\frac{1}{2}Cl_{2}(g) + \frac{1}{2}O_{2}(g) \rightarrow ClO(g)$

And, the given enthalpy is as follows.

$\frac{1}{2}Cl_{2}(g) + O_{2}(g) \rightarrow ClO_{2}(g)$ ; $\Delta H$ = 102.5 kJ

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Since, the bond enthalpy of Cl-Cl is not given so at first, we will calculate the value of Cl-Cl as follows.

$\Delta H = \sum \text{bond broken in reactants} - \sum \text{bond broken in products}$

102.5 = $[(\frac{1}{2})x + 498] - [(2)(243)]$

102.5 = $(\frac{1}{2})x + 498 - 486$

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x = 181 kJ

Now, total bond enthalpy of per mole of ClO is calculated as follows.

$\Delta H = \sum E(\text{bond broken in reactants}) - \sum (\text{bond broken in products})$

x = $[(\frac{1}{2})181 + (\frac{1}{2})498] - 243$

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Thus, we can conclude that the value for the enthalpy of formation per mole of ClO(g) is 96.5 kJ.

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3 years ago