The solution would be like
this for this specific problem:
<span>25.0 g CCl4 x (1 mole CCl4
/ 153.8 g CCl4) = 0.163 moles CCl4
</span>(29.82 kJ / mole)(0.163 moles) = 4.86 kJ
total heat = 1.11 kJ + 4.86 kJ = 5.97 kJ
<span>I hope this helps and if you have
any further questions, please don’t hesitate to ask again. </span>
Answer:
d. The correct answer for your questions is Sr<Ca<Be
C because it is and I know
Answer:
14.77 mol.
Explanation:
- It is known that every 1.0 mole of compound or element contains Avogadro's number (6.022 x 10²³) of molecules or atoms.
<u><em>Using cross multiplication:</em></u>
1.0 mole of He contains → 6.022 x 10²³ atoms.
??? mole of He contains → 8.84 x 10²⁴ atoms.
<em>∴ The no. of moles of He contains (8.84 x 10²⁴ atoms) </em>= (1.0 mol)(8.84 x 10²⁴ atoms)/(6.022 x 10²³ atoms) =<em> 14.77 mol.</em>
The specific heat : c = 0.306 J/g K
<h3>Further explanation</h3>
Given
Heat = 35.2 J
Mass = 16 g
Temperature difference : 7.2 K =
Required
The specific heat
Solution
Heat can be calculated using the formula:
Q = mc∆T
Q = heat, J
m = mass, g
c = specific heat, joules / g ° C
∆T = temperature difference, ° C / K
Input the value :
c = Q / m.∆T
c = 35.2 / 16 x 7.2
c = 0.306 J/g K
