If you sketch a Lewis dot structure of I3-, you'll perceive
that the center I atom formulates two bonds, and also has three non-bonding
pairs of electrons. That's an over-all of five electron pairs - beyond an
octet. Lots of compounds disrupt the octet rule that means, but the first long-row
elements like F can't because the lower elements like iodine can use an obtainable
d-orbital to house the additional pair of electrons (sp3d hybridization), but F
just doesn't have a d-orbital that it can use.
<span> </span>
<u>Answer:</u> Maximum work that can be obtained by given amount of methanol is -343kJ.
<u>Explanation:</u>
For the given chemical reaction:
By Stoichiometry of the reaction:
2 moles of methanol does a work of 1372 kJ.
So, 0.5 moles of methanol will do a work of = 
Hence, maximum work that can be obtained by given amount of methanol is -343kJ.
Answer:
B = A/DH – C
Explanation:
From the question given above, we obtained:
A = D • H(B + C)
Thus, we can obtain B in terms of D, H, A and C by doing the following:
A = D • H(B + C)
A = DH(B + C)
Divide both side by DH
A/DH = B + C
Subtract C from both side
A/DH – C = B + C – C
A/DH – C = B
B = A/DH – C
Answer;
B. They are large molecules that increase the rate of biologically important reactions.
Explanation;
-Enzymes are biological molecules, that are protein in nature, that significantly speed up the rate of virtually all of the chemical reactions that take place within cells.
-They are vital for life and serve a wide range of important functions in the body, such as aiding in digestion and metabolism. Some enzymes help break large molecules into smaller pieces that are more easily absorbed by the body. Other enzymes help bind two molecules together to produce a new molecule.
Answer:
B)−6,942 J
/mol
Explanation:
At constant temperature and pressure, you cand define the change in Gibbs free energy, ΔG, as:
ΔG = ΔH - TΔS
Where ΔH is enthalpy, T absolute temperature and ΔS change in entropy.
Replacing (25°C = 273 + 25 = 298K; 25.45kJ/mol = 25450J/mol):
ΔG = ΔH - TΔS
ΔG = 25450J/mol - 298K×108.7J/molK
ΔG = -6942.6J/mol
Right solution is:
<h3>B)−6,942 J
/mol</h3>
