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DanielleElmas [232]
4 years ago
6

Write two fractions where the LCD is 20, but the product of the denominators is not 20.

Mathematics
1 answer:
Dmitrij [34]4 years ago
6 0
Here are two possible fractions.   \frac{1}{20} \frac{1}{10}
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velikii [3]

Answer:

maybe it's 10.because c is 10,b is 10,and so as s.

hence s is 10 also.

7 0
4 years ago
What is the mode of the data? 4,3,2,1,0,2,3,1,4,3
AURORKA [14]

Answer: 3

Step-by-step explanation:

8 0
4 years ago
Show in fact that 1=9m + 20n for some integers m and n
marta [7]

Answer:

1=9\cdot 9+20\cdpt (-4)=81-80

Step-by-step explanation:

The greatest common divisor between 9 and 20 is 1, so we know the equation 1=9m+20n has a solution. A solution can be found either by inspection, or by applying Euclidean algorithm.

By inspection we just list some multiples of 9:

9, 18, 27, 36, 45, 54, 63, 72, 81, 90, 99

and also list some mutiples of 20:

20, 40, 60, 80, 100, 120

And so we see that we can find a multiple of 9 (81) which is 1 away from a multiple of 20 (80). Which is the solution given at the start.

For the Euclidean algorithm, we should divide the greatest of the two numbers, by the smallest one, and keep track of the remainder:

20 = 9 * 2 + 2

Then we divide 9 by the remainder we got, which is 2:

9 =  2 * 4 + 1

we would continue doing this until getting a remainder of 1 (which we just did). Finally we "solve" for 1, from the last equation:

9 - 2*4 = 1

And then we solve for 2 from the first equation, and plug that in into the previous equation:

20 - 9*2 =2

9 - ( 20 - 9*2)*4 = 1

which does give us the same solution: 9\cdot 9 +20\cdot (-4)=1

5 0
4 years ago
the weight of an object on mars varies directly as the weight of the object on earth a 90 pound object on earth weighs 34 pounds
Mariulka [41]

We have been given that the weight of an object on the mars varies directly as the weight of the object on earth.  

Let y be weight of an object on Mars and x be weight of an object on Earth.

\\
y=kx

We have been given that the weight of an object on Mars is 34 pounds and weight of the same object on Earth is 90 pounds.

Putting the given values in equation we get

\\
34=k(90)\\
\\
k=\frac{34}{90}=\frac{17}{45}

Therefore, our equation now becomes

\\
y= \frac{17}{45}x

Now we have been given that the weight of an object on Earth is 135 pounds and we have to find the weight of the same object on Mars,

We have been given that \\
x=135

Putting the given values in our equation we get

\\
y= \frac{17}{45}(135)=\frac{17\cdot 135}{45}=17\cdot 3 = 51

Therefore weight of the object on Mars will be 51 pounds.

                                                                             

7 0
4 years ago
Read 2 more answers
Help I need to get this done I need the work
In-s [12.5K]
Question 5:
7x3x4= 84 cubic inches

Question 6
4x4x4= 64 ft cubed

Question 7:
?

Question 8:
5x5x5= 125 cube cm

Sorry I don’t know about question 7 :(
6 0
3 years ago
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