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3 years ago

10

Using the information given in this description, explain whether the pulse will reflect as a trough or a crest under the followi

ng conditions.
At boundary A, the reflected pulse will be a _____.

1 answer:

loris [4]3 years ago

7 0

Answer:

jesus

Explanation:

For God so loved the world that He gave his one and only Son, that whoever believes in Him shall not perish but have eternal life." "As a mother comforts her child, so I will comfort you; in Jerusalem you shall find your comfort." "Then shall the righteous shine forth as the sun in the kingdom of the Father.

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A 1kw electric heater is switched on for ten minutes. how much heat does it produce

Ainat [17]

H= P × t

1kW= 1000w

10 min = 600s

H= 1000×600=600,000J

=> 143.40kcal

4 0

3 years ago

a man throws a football straight into the air. As it rises,it slows down. Which type of energy is the football gaining?

kotykmax [81]

It is gaining potental energy which will then transfer to knetic energy as it falls

5 0

3 years ago

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A student sits on a rotating stool holding two 3.09-kg masses. When his arms are extended horizontally, the masses are 1.08 m fr

schepotkina [342]

Answer:

a

The New angular speed is $w_f = 2.034 rad/s$

b

The Kinetic energy before the masses are pulled in is $KE_i = 3.101 \ J$

c

The Kinetic energy after the masses are pulled in is $KE_f = 8.192 \ J$

Explanation:

From the we are told that masses are 1.08 m from the axis of rotation, this means that

The radius $r =1.08m$

The mass is $m = 3.09\ kg$

The angular speed $w = 0.770 \ rad/sec$

The moment of inertia of the system excluding the two mass $I = 3.25 \ kg \cdot m^2$

New radius $r_{new} = 0.34m$

Generally the conservation of angular momentum can be mathematical represented as

$w_f = [\frac{I_i}{I_f} ]w_i .....(1)$

Where $w_f$ is the final angular speed

$w_i$ is the initial angular speed

$I_i$ is the initial moment of inertia

$I_f$ is the final moment of inertia

Moment of inertia is mathematically represented as

$I = m r^2$

Where I is the moment of inertia

m is the mass

r is the radius

So the Initial moment of inertia is given as

$I_i = moment \ of \ inertia \ of\ the \ two \ mass \ + 3.25 \ kg \cdot m^2$

$I_i = 2m r^2 + 3.25$

The multiplication by is because we are considering two masses

$I_i = 2 [(3.09)(1.08)^2] +3.25 = 10.46 kg \cdot m^2$

So the final moment of inertia is given as

$I_f = 2[(3.09)(0.34)^2] +3.25 = 3.96 \ kg \cdot m^2$

Substituting these values into equation 1

$w_f = [\frac{10.46}{3.96} ] * 0.77 = 2.034 \ rad/sec$

Generally Kinetic energy is mathematically represented in term of moment of inertia as

$KE = \frac{1}{2} * I * w^2$

Now considering the kinetic energy before the masses are pulled in,

$KE_i = \frac{1}{2} * I_i * w^2_i$

The Moment of inertia would be $I_i = 10.46 \ Kg \cdot m^2$

The Angular speed would be $w_i = 0.77 \ rad/s$

Now substituting these value into the equation above

$KE_i = \frac{1}{2} * (10.46) * (0.770)^2 = 3.101 J$

Now considering the kinetic energy after the masses are pulled in,

$KE_f = \frac{1}{2} * I_f * w^2_f$

The Moment of inertia would be $I_f = 3.96 \ Kg \cdot m^2$

The Angular speed would be $w_f = 2.034 \ rad/s$

Now substituting these value into the equation above

$KE_f= \frac{1}{2} *(3.96)(2.034)^2$

$= 8.192J$

8 0

3 years ago

A piston uses 32 J of energy to do work as 68 J of heat are added to the cylinder of the piston. The change in internal energy o

enyata [817]

Internal energy<span> is defined as the </span>energy<span> associated with the random, disordered motion of molecules. It is denoted by U and calculated by the expression:

</span>Δ<span>U = Q - W

We calculate as follows:

</span>ΔU = 68 J - 32 J
ΔU = 36 J

3 0

3 years ago

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How do you use a Beam Balance???<br>

zepelin [54]

Explanation:

<h3>The beam balance is a device used</h3><h3> for the determination of the mass of </h3><h3>a body under gravitation. It consists </h3><h3>of a beam supported at the centre </h3><h3>by an agate knife edge resting on a</h3><h3> support moving inside a vertical </h3><h3>pillar. The beam carries a light</h3><h3>pointer which moves over a scale.</h3>

4 0

3 years ago

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