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stira [4]
2 years ago
10

What is the velocity of an object that has been in free fall for 2.5 s?

Physics
1 answer:
Vaselesa [24]2 years ago
6 0

After 2.5 seconds of free fall, an item will be moving downhill at a speed of 25 m/s.Option D is correct.

<h3>What is velocity?</h3>

The change of displacement with respect to time is defined as speed. Speed is a scalar quantity. It is a time-based component. Its unit is m/sec.

The given data in the problem is;

t(time)= 2.5 s

u(falling velocity)=0 m/sec

v(striking velocity)=?  (m/sec)

Newton's first equation of motion:

v=u+at

v=u+gt

v=10 × 2.5

v= 25 m/s downward(+ ve taken as downward)

The velocity of an object that has been in free fall for 2.5 s will be 25  m/s downward.

Hence, option D is correct.

To learn more about the velocity refer to the link;

brainly.com/question/862972

#SPJ1

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An egg is thrown horizontally off the top row bleachers at the Brickyard,
Ludmilka [50]

Answer:

4

Explanation:

Divide 30 meters by 7.5 and you´re answer is 4. This is how I would think you solve the problem

6 0
3 years ago
Find the mass of 250 mL of water. The density of water is 1 g/mL.​
emmainna [20.7K]

Answer:

<h2>The answer is 250 g</h2>

Explanation:

The mass of a substance when given the density and volume can be found by using the formula

<h3>mass = Density × volume</h3>

From the question

volume = 250 mL

density = 1 g/mL

So we have

mass = 250 × 1

We have the final answer as

<h3>250 g</h3>

Hope this helps you

4 0
3 years ago
Calculate the wavelength of a photon having 3.26 x 10^-19 joules of energy
bekas [8.4K]
The energy of a photon is given by:
E=hf
where h is the Planck constant and f is the photon frequency.
We know the energy of the photon, E=3.26 \cdot 10^{-19} J, so we can rearrange the equation to calculate the frequency of the photon:
f= \frac{E}{h}= \frac{3.26 \cdot 10^{-19}J}{6.6 \cdot 10^{-34}Js}=4.94 \cdot 10^{14}Hz

And now we can use the following relationship between frequency f, wavelength \lambda and speed of light c to find the wavelength of the photon:
\lambda= \frac{c}{f}= \frac{3 \cdot 10^8 m/s}{4.94 \cdot 10^{14} Hz}=6.07\cdot 10^{-7} m=607 nm
8 0
3 years ago
A current I flows down a wire of radius a.
Helga [31]

Answer:

(a) K = \frac{I}{2\pi a}

(b) J = \frac{I}{2\pi as}

Explanation:

(a) The surface current density of a conductor is the current flowing per unit length of the conductor.

                                   K = \frac{dI}{dL}

Considering a wire, the current is uniformly distributed over the circumferenece of the wire.

                                   dL = 2\pi r

The radius of the wire = a

                                    dL = 2\pi a

The surface current density K = \frac{I}{2\pi a}

(b) The current density is inversely proportional

                                     J \alpha  s^{-1}    

                                     J = \frac{k}{s}           ......(1)

k is the constant of proportionality

                                     I = \int\limits {J} \, dS

                                     I = J \int\limits \, dS     ........(2)

substituting (1) into (2)

                                     I = \frac{k}{s} \int\limits\, dS

                                     I = k \int\limits^a_0 \frac{1}{s}  {s} \, dS

                                     I = 2\pi k\int\limits\, dS

                                     I = 2\pi ka

                                     k = \frac{I}{2\pi a}

substitute J = \frac{k}{s}

                                     J = \frac{I}{2\pi as}

7 0
3 years ago
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iren2701 [21]
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Hope this helps :)
6 0
3 years ago
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