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2 years ago

What is the velocity of an object that has been in free fall for 2.5 s?

Physics

1 answer:

Vaselesa [24]2 years ago

6 0

After 2.5 seconds of free fall, an item will be moving downhill at a speed of 25 m/s.Option D is correct.

<h3>What is velocity?</h3>

The change of displacement with respect to time is defined as speed. Speed is a scalar quantity. It is a time-based component. Its unit is m/sec.

The given data in the problem is;

t(time)= 2.5 s

u(falling velocity)=0 m/sec

v(striking velocity)=? (m/sec)

Newton's first equation of motion:

v=u+at

v=u+gt

v=10 × 2.5

v= 25 m/s downward(+ ve taken as downward)

The velocity of an object that has been in free fall for 2.5 s will be 25 m/s downward.

Hence, option D is correct.

To learn more about the velocity refer to the link;

brainly.com/question/862972

#SPJ1

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An egg is thrown horizontally off the top row bleachers at the Brickyard,

Ludmilka [50]

Answer:

Explanation:

Divide 30 meters by 7.5 and you´re answer is 4. This is how I would think you solve the problem

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3 years ago

Find the mass of 250 mL of water. The density of water is 1 g/mL.

emmainna [20.7K]

Answer:

<h2>The answer is 250 g</h2>

Explanation:

The mass of a substance when given the density and volume can be found by using the formula

<h3>mass = Density × volume</h3>

From the question

volume = 250 mL

density = 1 g/mL

So we have

mass = 250 × 1

We have the final answer as

Hope this helps you

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3 years ago

Calculate the wavelength of a photon having 3.26 x 10^-19 joules of energy

bekas [8.4K]

The energy of a photon is given by:
$E=hf$
where h is the Planck constant and f is the photon frequency.
We know the energy of the photon, $E=3.26 \cdot 10^{-19} J$ , so we can rearrange the equation to calculate the frequency of the photon:
$f= \frac{E}{h}= \frac{3.26 \cdot 10^{-19}J}{6.6 \cdot 10^{-34}Js}=4.94 \cdot 10^{14}Hz$

And now we can use the following relationship between frequency f, wavelength $\lambda$ and speed of light c to find the wavelength of the photon:
$\lambda= \frac{c}{f}= \frac{3 \cdot 10^8 m/s}{4.94 \cdot 10^{14} Hz}=6.07\cdot 10^{-7} m=607 nm$

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3 years ago

A current I flows down a wire of radius a.

Helga [31]

Answer:

(a) $K = \frac{I}{2\pi a}$

(b) $J = \frac{I}{2\pi as}$

Explanation:

(a) The surface current density of a conductor is the current flowing per unit length of the conductor.

$K = \frac{dI}{dL}$

Considering a wire, the current is uniformly distributed over the circumferenece of the wire.

$dL = 2\pi r$

The radius of the wire = a

$dL = 2\pi a$

The surface current density $K = \frac{I}{2\pi a}$

(b) The current density is inversely proportional

$J \alpha s^{-1}$

$J = \frac{k}{s}$ ......(1)

k is the constant of proportionality

$I = \int\limits {J} \, dS$

$I = J \int\limits \, dS$ ........(2)

substituting (1) into (2)

$I = \frac{k}{s} \int\limits\, dS$

$I = k \int\limits^a_0 \frac{1}{s} {s} \, dS$

$I = 2\pi k\int\limits\, dS$

$I = 2\pi ka$

$k = \frac{I}{2\pi a}$

substitute $J = \frac{k}{s}$

$J = \frac{I}{2\pi as}$

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iren2701 [21]

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Hope this helps :)

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3 years ago