Answer:
Tungsten wire is used as the filament in light bulbs. It glows white-hot as current passes through it.
Tungsten is used in light bulbs because its high <u>RESISTANCE</u> converts electric energy into light and heat.
Explanation:
Answer:
thermal energy
Explanation:
heat transfers into it causing it to physically change
Answer:
5.31143691523 m/s²
Explanation:
m = Mass = 280 g
x = Displacement of spring = 21.7 cm
Time period
![T=\dfrac{14}{11}\\\Rightarrow T=1.27\ s](https://tex.z-dn.net/?f=T%3D%5Cdfrac%7B14%7D%7B11%7D%5C%5C%5CRightarrow%20T%3D1.27%5C%20s)
Angular velocity is given by
![\omega=\dfrac{2\pi}{T}\\\Rightarrow \omega=\dfrac{2\pi}{1.27}\\\Rightarrow \omega=4.94739\ rad/s](https://tex.z-dn.net/?f=%5Comega%3D%5Cdfrac%7B2%5Cpi%7D%7BT%7D%5C%5C%5CRightarrow%20%5Comega%3D%5Cdfrac%7B2%5Cpi%7D%7B1.27%7D%5C%5C%5CRightarrow%20%5Comega%3D4.94739%5C%20rad%2Fs)
![\omega=\sqrt{\dfrac{k}{m}}\\\Rightarrow k=\omega^2m\\\Rightarrow k=4.94739^2\times 0.28\\\Rightarrow k=6.85346698739\ N/m](https://tex.z-dn.net/?f=%5Comega%3D%5Csqrt%7B%5Cdfrac%7Bk%7D%7Bm%7D%7D%5C%5C%5CRightarrow%20k%3D%5Comega%5E2m%5C%5C%5CRightarrow%20k%3D4.94739%5E2%5Ctimes%200.28%5C%5C%5CRightarrow%20k%3D6.85346698739%5C%20N%2Fm)
From Hooke's law
![mg=kx\\\Rightarrow g=\dfrac{kx}{m}\\\Rightarrow g=\dfrac{6.85346698739\times 0.217}{0.28}\\\Rightarrow g=5.31143691523\ m/s^2](https://tex.z-dn.net/?f=mg%3Dkx%5C%5C%5CRightarrow%20g%3D%5Cdfrac%7Bkx%7D%7Bm%7D%5C%5C%5CRightarrow%20g%3D%5Cdfrac%7B6.85346698739%5Ctimes%200.217%7D%7B0.28%7D%5C%5C%5CRightarrow%20g%3D5.31143691523%5C%20m%2Fs%5E2)
The acceleration due to gravity on the planet is 5.31143691523 m/s²
Yes, I have been able to satisfy my curiosity.
Answer:
The distance by the ball clear the crossbar is 1.15 m
Explanation:
Given that,
Distance = 44 m
Speed = 24 m/s
Angle = 31°
Height = 3.05 m
We need to calculate the horizontal velocity
Using formula of horizontal velocity
![u_{x}=u\cos\theta](https://tex.z-dn.net/?f=u_%7Bx%7D%3Du%5Ccos%5Ctheta)
Put the value into the formula
![u_{x}=24\cos(31)](https://tex.z-dn.net/?f=u_%7Bx%7D%3D24%5Ccos%2831%29)
![u_{x}=20.5\ m/s](https://tex.z-dn.net/?f=u_%7Bx%7D%3D20.5%5C%20m%2Fs)
We need to calculate the vertical velocity
Using formula of vertical velocity
![u_{y}=u\sin\theta](https://tex.z-dn.net/?f=u_%7By%7D%3Du%5Csin%5Ctheta)
Put the value into the formula
![u_{y}=24\sin(31)](https://tex.z-dn.net/?f=u_%7By%7D%3D24%5Csin%2831%29)
![u_{y}=12.3\ m/s](https://tex.z-dn.net/?f=u_%7By%7D%3D12.3%5C%20m%2Fs)
We need to calculate the time
Using formula of time
![t=\dfrac{d}{u_{x}}](https://tex.z-dn.net/?f=t%3D%5Cdfrac%7Bd%7D%7Bu_%7Bx%7D%7D)
Put the value into the formula
![t=\dfrac{44}{20.5}](https://tex.z-dn.net/?f=t%3D%5Cdfrac%7B44%7D%7B20.5%7D)
![t=2.1\ sec](https://tex.z-dn.net/?f=t%3D2.1%5C%20sec)
We need to calculate the vertical height
Using equation of motion
![h=u_{y}t+\dfrac{1}{2}at^2](https://tex.z-dn.net/?f=h%3Du_%7By%7Dt%2B%5Cdfrac%7B1%7D%7B2%7Dat%5E2)
Put the value into the formula
![h=12.3\times2.1-\dfrac{1}{2}\times9.8\times(2.1)^2](https://tex.z-dn.net/?f=h%3D12.3%5Ctimes2.1-%5Cdfrac%7B1%7D%7B2%7D%5Ctimes9.8%5Ctimes%282.1%29%5E2)
![h=4.2\ m](https://tex.z-dn.net/?f=h%3D4.2%5C%20m)
We need to calculate the distance by the ball clear the crossbar
Using formula for vertical distance
![d=h-3.05](https://tex.z-dn.net/?f=d%3Dh-3.05)
Put the value of h
![d=4.2-3.05](https://tex.z-dn.net/?f=d%3D4.2-3.05)
![d=1.15\ m](https://tex.z-dn.net/?f=d%3D1.15%5C%20m)
Hence, The distance by the ball clear the crossbar is 1.15 m
It could be stress or strain