1. If the atomic number is 25, how many protons does it have?

A passenger at an airport pulls a rolling suitcase by its handle. If the force used is 10 N and the handle makes an angle of 25

Deffense [45]

Answer:

W= 1812.6 J

Explanation:

Work (W) is defined as the scalar product of force F by the distance (d) the body travels due to this force.

W= F*d* cosα Formula ( 1)

Where:

F is the force in Newtons (N)

d is the displacemente in meters (m)

α : Angle formed between force and displacement

Data

F = 10 N

d = 200 m

α = 25°

Work done by the pulling force while the passenger walks 200 m

We replace data in the formula (1)

W= F*d* cosα

W= (10 N)*(200 m)* cos25°

W= 1812.6 (N*m)

W= 1812.6 J

6 0

3 years ago

At time t=0 a positively charged particle of mass m=3.57 g and charge q=9.12 µC is injected into the region of the uniform magne

larisa [96]

Answer:

10.78 s

Explanation:

The force on the charge is computed by using the equation:

$F^{\to}= qE^{\to} +q (v^{\to} + B^{\to}) \\ \\ F^{\to} = (9.12 \times 10^{-6}) *278 (-\hat k) +9.12 *10^{-6} *2.1 *0.18 (\hat i * \hat k) \\ \\ F^{\to} = -2.535 *10^{-3} \hat k -3.447*10^{-6} \hat j$

F = ma

∴

$a ^{\to}= \dfrac{F^{\to}}{m}$

$a ^{\to}= \dfrac{-1}{3.57\times 10^{-3}}(2.535*10^{-3}\hat k + 3.447*10^{-6} \hat j)$

$a ^{\to}=-0.710 \hat k -9.656*10^{-4} \hat j$

At time t(sec; the partiCle velocity becomes $v(t) = 3.78 v_o$

The velocity of the charge after the time t(sec) is expressed by using the formula:

$v^{\to}= v_{o \ \hat i} + a^{\to }t \\ \\ \implies (2.1)\hat i -0.710 t \hat k -9.656 \times 10^{-4} t \hat j = 3.78 v_o \\ \\ \implies (2.1)^2 +(0.710\ t)^2+ (9.656 *10^{-4}t )^2 = (3.78 *2.1^2 \\ \\ \implies 4.41 +0.5041 t^2 +9.324*10^{-7} t^2 = 63.012 \\ \\ \implies 4.41 +0.5041 t^2 = 63.012\\ \\ 0.5041t^2 = 63.012-4.41 \\ \\ t^2 = \dfrac{58.602}{0.5041} \\ \\ t^2 = 116.25 \\ \\ t = \sqrt{116.25} \\ \\ \mathbf{t = 10.78 \ s}$

8 0

3 years ago

Which quantity or quantities is/are increasing for the object represented by line B?

torisob [31]

Answer:

C. Velocity and Position

Explanation:

7 0

3 years ago

A) Define rest and motion?

7nadin3 [17]

Answer:

Rest - a body is said to be at rest, if it does not change its position with respect to its surrounding with time. Motion - a body is said to be at motion, if it changes its position with time.

5 0

3 years ago

Two girls stand 500m away from a tall wall

Mama L [17]

From the calculations, the speed of sound in this case is 16.9 m/s.

The term echo has to do with the reflection of sound waves. Sound is a mechanical wave.

we know that the speed of sound is obtained from;

V = 2x/t

x = distance covered

t = time taken

V = 2(500)/59

v = 16.9 m/s

The error in the experiment could come from;

Lack of precise time measurement
Error can also arise from the environment of the experiment

Learn more about echo:brainly.com/question/9527413

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4 0

2 years ago