Answer:
The answer is: Increase the Number of Ropes/Pulleys.
Explanation:
A "pulley" <u><em>is an object that supports a particular movement such as supporting a force's change in direction (provided that the direction is applied to a cord). </em></u>This is regarded as a "simple machine" consisting of a wheel on an axle. This helps guide cables or ropes.
This machine is used <em>in order to decrease the amount of time it takes to do work, such as lifting of objects.</em>
Remember that "mechanical advantage"<u> refers to the ratio between the force applied to a machine and the force produced by it.</u> So, when it comes to pulleys, the mechanical advantage increases when the number of ropes are also increased. They are directly proportional. This goes the same way with increasing the number of pulleys. Once you increase the number of pulleys, the mechanical advantage also increases.
Hi Pupil Here's Your answer :::
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Answer : When a man jumps out from a boat, he pushes the boat with his feet (action) and the boat also exert an equal force on him in opposite direction reaction. As a result, the man jumps to the bank and the boat moves in the backward direction.
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Hope this helps . . . . . .
The fetus relies upon its mother as it develops. These are some of the things it needs:
<span>protection against knock and bumps, and temperature changes
oxygen for respiration
nutrients (food and water)
</span>
The developing fetus also needs its waste substances removing.
The fetus is protected by the uterus and the amniotic fluid, a liquid contained in a bag called the amnion.
(A) The total initial momentum of the system is
(1.30 kg) (27.0 m/s) + (23.0 kg) (0 m/s) = 35.1 kg•m/s
(B) Momentum is conserved, so that the total momentum of the system after the collision is
35.1 kg•m/s = (1.30 kg + 23.0 kg) <em>v</em>
where <em>v</em> is the speed of the combined blocks. Solving for <em>v</em> gives
<em>v</em> = (35.1 kg•m/s) / (24.3 kg) ≈ 1.44 m/s
(C) The kinetic energy of the system after the collision is
1/2 (1.30 kg + 23.0 kg) (1.44 m/s)² ≈ 25.4 J
and before the collision, it is
1/2 (1.30 kg) (27.0 m/s)² ≈ 474 J
so that the change in kinetic energy is
∆<em>K</em> = 25.4 J - 474 J ≈ -449 J
