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Harlamova29_29 [7]
3 years ago
13

If a given solution has a 30 percent solute concentration, and more solute is added to the solution, the new solute concentratio

n could be:
Chemistry
1 answer:
Lerok [7]3 years ago
7 0
If a given solution has a 30% solute concentration and that more of the solute would be added to the mixture, then the new concentration of the solute would be higher than the original since more solute is present in the solution. Concentration will always be the amount of a substance in a mixture per amount of the solvent or the solution. So, concentration and the amount of solute has a direct relation.
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What’s the difference between an ester and an amide
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Aluminum reacts with chlorine gas to form aluminum chloride via the following reaction: 2Al(s)+3Cl2(g)→2AlCl3(s) What is the max
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<u>Answer:</u> The mass of aluminium chloride that can be formed are 46.3 g

<u>Explanation:</u>

To calculate the number of moles, we use the equation:

\text{Number of moles}=\frac{\text{Given mass}}{\text{Molar mass}}  ....(1)  

  • <u>For Aluminium:</u>

Given mass of aluminium = 32 g  

Molar mass of aluminium = 26.98 g/mol

Putting values in above equation, we get:  

\text{Moles of aluminium}=\frac{32g}{26.98g/mol}=1.186mol

  • <u>For Chlorine:</u>

Given mass of chlorine = 37 g  

Molar mass of chlorine = 71 g/mol

Putting values in above equation, we get:  

\text{Moles of chlorine gas}=\frac{37g}{71g/mol}=0.521mol

For the given chemical equation:

2Al(s)+3Cl_2(g)\rightarrow 2AlCl_3(s)

By Stoichiometry of the reaction:

3 moles of chlorine gas is reacting with 2 moles of aluminium.

So, 0.521 moles of chlorine gas will react with = \frac{2}{3}\times 0.521=0.347moles of aluminium.

As, given amount of aluminium is more than the required amount. Thus, it is considered as an excess reagent.

So, chlorine gas is considered as a limiting reagent because it limits the formation of products.

By Stoichiometry of the reaction:

3 moles of chlorine gas is producing 2 moles of aluminium chloride

So,  0.521 moles of chlorine gas will react with = \frac{2}{3}\times 0.521=0.347moles of aluminium chloride.

Now, calculating the mass of aluminium chloride by using equation 1, we get:

Moles of aluminium chloride = 0.347 moles

Molar mass of aluminium chloride = 133.34 g/mol

Putting all the values in equation 1, we get:

0.347mol=\frac{\text{Mass of aluminium chloride}}{133.34g/mol}\\\\\text{Mass of aluminium chloride}=46.3g

Hence, the mass of aluminium chloride that can be formed are 46.3 g

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Water is a solute. solvent.
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solvent

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