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Brut [27]
3 years ago
14

A 25.0 ml sample of aqueous sodium hydroxide has been used to titrate to the second equivalence point 22.30 ml of 0.253 m sulfur

ic acid. What is the molarity of the sodium hydroxide solution?
Chemistry
1 answer:
adelina 88 [10]3 years ago
3 0

The molarity of the sodium hydroxide is calculated by first calculating the number of moles of sulfuric acid in the 22.30 ml used.

This is done as follows since 0.253M is contained in 1000ml solution.

(0.253×22.3)/1000=0.00564 moles

The equation for the reaction is:

H₂SO₄₍ₐq)+2NaOH₍ₐq)⇒ Na₂SO₄₍aq) +2 H₂O₍l₎

Therefore the reacting ratios between sodium hydroxide and sulfuric acid is 2:1

therefore the number of moles that reacted with the sulfuric acid is calculated as follows:

(0.00564 moles ₓ 2)/1=0.01128moles

0.1128moles is in 25ml therefore, 1000ml has:

(1000ₓ0.01128moles)/25= 0.4512M NaOH

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Answer:

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So after losing this electron positive charge on the upper right side of the atom will occur with the number of electron lose that is Na+1 .

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3 years ago
Formed when an amine is combined with a carboxyl group
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Have a nice day
7 0
3 years ago
The source of bitterness in dark chocolate is the compound theobromine, an alkaloid present in cocoa beans. In a sample of dark
spin [16.1K]

Answer: 193 mg of theobromine are present in the sample.

Explanation:

According to avogadro's law, 1 mole of every substance occupies 22.4 L at STP and contains avogadro's number of particles.

To calculate the moles, we use the equation:

\text{Number of moles}=\frac{\text{Given molecules}}{\text {Avogadros number}}=\frac{6.45\times 10^{20}}{6.023\times 10^{23}}=1.07\times 10^{-3}moles

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1.07\times 10^{-3}moles  of theobromine (C_7H_8N_4O_2) weigh = \frac{180}{1}\times 1.07\times 10^{-3}=0.193g=193mg   (1g=1000mg)

193 mg of theobromine are present in the sample.

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3 years ago
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