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dangina [55]
3 years ago
7

I need help with my 8th grade math

Mathematics
1 answer:
lana [24]3 years ago
6 0

Answer:

x = -2.38

Step-by-step explanation:

divide 3 to up 3x then 4 and divide them by 2.

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If prices increase at a monthly rate of 3.4​%, by what percentage do they increase in a​ year?
crimeas [40]
40.8%  I hope this helps!
7 0
3 years ago
35% of the students at charles drew middle school are 6th graders if there are 84 sixth graders what is the total number of stud
Juliette [100K]

Answer: The total number of student in the school  = 240.

Step-by-step explanation:

Let x be the total number of students in the school.

Given: 35% of the students at Charles drew middle school are 6th graders.

i.e. Number of sixth graders = 35% of x = 0.35x   [35% = 0.35]

Since there are 84 sixth graders in the school,

So  0.35x=84

Divide both sides by 0.35, we get

x=\dfrac{84}{0.35}=\dfrac{84\times100}{35}=240

Hence, the total number of student in the school  = 240.

6 0
3 years ago
rosy has 16 pencils and 24 erasers. she is putting together packets that will have an equal number of pencils and erasers in eac
faust18 [17]

Answer:48

Step-by-step explanation: you were indirectly asked for the L.C. M of 16 and 24

4 0
3 years ago
Arrange the geometric series from least to greatest based on the value of their sums.
son4ous [18]

Answer:

80 < 93 < 121 < 127

Step-by-step explanation:

For a geometric series,

\sum_{t=1}^{n}a(r)^{t-1}

Formula to be used,

Sum of t terms of a geometric series = \frac{a(r^t-1)}{r-1}

Here t = number of terms

a = first term

r = common ratio

1). \sum_{t=1}^{5}3(2)^{t-1}

   First term of this series 'a' = 3

   Common ratio 'r' = 2

   Number of terms 't' = 5

   Therefore, sum of 5 terms of the series = \frac{3(2^5-1)}{(2-1)}

                                                                      = 93

2). \sum_{t=1}^{7}(2)^{t-1}

   First term 'a' = 1

   Common ratio 'r' = 2

   Number of terms 't' = 7

   Sum of 7 terms of this series = \frac{1(2^7-1)}{(2-1)}

                                                    = 127

3). \sum_{t=1}^{5}(3)^{t-1}

    First term 'a' = 1

    Common ratio 'r' = 3

    Number of terms 't' = 5

   Therefore, sum of 5 terms = \frac{1(3^5-1)}{3-1}

                                                 = 121

4). \sum_{t=1}^{4}2(3)^{t-1}

    First term 'a' = 2

    Common ratio 'r' = 3

    Number of terms 't' = 4

    Therefore, sum of 4 terms of the series = \frac{2(3^4-1)}{3-1}

                                                                       = 80

    80 < 93 < 121 < 127 will be the answer.

4 0
3 years ago
Read 2 more answers
In the first quadrant, you start at ( 6, 5 ) and move 3 units left .
Verdich [7]

Answer:

(3,5)

∧

this is x number

Step-by-step explanation:

the x number is left and right movement. if you move 3 units left you would subtract 3 from the x number. so 6-3=3 and you don't have to do anything on the y value because you don't move it.

3 0
3 years ago
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