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maksim [4K]
3 years ago
12

The ordered pair below is a solution to which equation?. . (3, 15). . A. y = 5x. B. y = 3x. C. y = 1/5x. D. y = 1/3x

Mathematics
1 answer:
Lelechka [254]3 years ago
3 0
The solution to the ordered pair (3,15) is the equation y = 5x, which is letter A. This is found by substituting the value of the x into the equation and solving for y. The equation y = 5x satisfies the ordered pair (3,15) because if you substitute x with 3, the equation becomes y = 5(3) which is 15.
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1. 4g= 37-5
 ⇒ 4g= 32
⇒ g= 32/4
⇒ g= 8

2. c= 5*6
⇒ c= 30

3. f+4= 3*5
⇒f+4= 15
⇒ f= 15-4
⇒ f= 11.

4. b+6= 30/5
⇒ b+6= 6
⇒ b= 6-6
⇒ b=0

5. a-5= 60/5
⇒ a-5= 12
⇒ a= 12+5
⇒ a= 17

6. e+2= 45/5
⇒ e+2= 9
⇒ e= 9-2
⇒ e= 7

7. d-5= 12/3
⇒ d-5= 4
⇒ d= 4+5
⇒ d= 9

8. m-4= 16/4
⇒ m-4= 4
⇒ m= 4+4
⇒ m= 8

9. q+6= 30/5
⇒ q+6= 6
⇒ q= 6-6
⇒ q= 0

10. h/3= 3+5
⇒ h/3= 8
⇒ h= 8*3
⇒ h= 24

11. 3c= 3-5
⇒ 3c= -2
⇒ c= -2/3

12. x/3= 6-7
⇒ x/3= -1
⇒ x= -1*3
⇒ x= -3

13. 6p= 2+1
⇒ 6p= 3
⇒ p= 3/6
⇒ p= 1/2

14. 2d-7= 27/3
⇒ 2d-7= 9
⇒ 2d= 9+7
⇒ 2d= 16
⇒ d= 16/2
⇒ d=8

15. b-3= 5/2
⇒ b-3= 2.5
⇒ b= 2.5+3
⇒ b= 5.5

16. y-1= 1/3
⇒ y= 1/3+1
⇒ y= 1 1/3

17. 5v= 9-3
⇒ 5v= 6
⇒ v= 6/5
⇒ v= 1.2

18. n-3 = 3*6
⇒ n-3= 18
⇒ n= 18+3
⇒ n= 21

19. t+10= 1*4
⇒ t+10= 4
⇒ t= 4-10
⇒ t= -6

20. 3c+4= 3*5
⇒ 3c+4= 15
⇒ 3c= 15-4
⇒ 3c= 11
⇒ c= 11/3
⇒ c= 3 2/3

Hope this helps~
6 0
4 years ago
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What is the product of 2p + q and –3q – 6p + 1?
Umnica [9.8K]
-12p^2 - 12pq + 2p -3q^2 + q
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3 years ago
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