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3 years ago

The ordered pair below is a solution to which equation?. . (3, 15). . A. y = 5x. B. y = 3x. C. y = 1/5x. D. y = 1/3x

1 answer:

3 0

The solution to the ordered pair (3,15) is the equation y = 5x, which is letter A. This is found by substituting the value of the x into the equation and solving for y. The equation y = 5x satisfies the ordered pair (3,15) because if you substitute x with 3, the equation becomes y = 5(3) which is 15.

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3 years ago

In ∆PQR, ∠P = 90degrees , PQ= 12 cm, PR=16cm. Find ∠Q

siniylev [52]

Answer:

∠Q = 53.13 degrees

Step-by-step explanation:

Given that ∆PQR, ∠P = 90degrees , this means that the triangle is a right angled triangle

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SOH CAH TOA

where S is sine, C is cosine, T is tangent and O, A and H represents the size of the opposite, adjacent and hypotenuse sides

Considering ∠Q and the given sides

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3 years ago

Given a polynomial f(x), if (x + 7) is a factor, what else must be true?

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3 years ago

In a statistics class there are 18 juniors and 10 seniors; 6 of the seniors are females and 12 of the juniors are males. If a st

Natasha_Volkova [10]

Answer:

P(a junior or a senior)=1

Step-by-step explanation:

The formula of the probability is given by:

$P(A)=\frac{n(A)}{N}$

Where P(A) is the probability of occurring an event A, n(A) is the number of favorable outcomes and N is the total number of outcomes.

In this case, N is the total number of the students of statistics class.

N=18+10=28

The probability of the union of two mutually exclusive events is given by:

$P(AUB)=P(A)+P(B)$

Therefore:

P(a junior or a senior) =P(a junior)+P(a senior)

Because a student is a junior or a senior, not both.

n(a junior)=18

n(a senior)=10

P(a junior)=18/28

P(a senior) = 10/28

P(a junior or a senior) = 18/28 + 10/28

Solving the sum of the fractions:

P(a junior or a senior) = 28/28 = 1

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3 years ago

joey's mom baked two dozen cookies . that night, there were only 14 cookies left. what percentage of the cookies were eaten?

Aleksandr [31]

Answer:

41.67 % ( to 2 dec. places )

Step-by-step explanation:

Since 2 dozen cookies were baked, that is 24 and 14 were left.

Then 10 were eaten.

Calculate the percentage eaten as

percentage = $\frac{numbereaten}{original}$ × 100%

percentage eaten = $\frac{10}{24}$ × 100% ≈41.67%

5 0

3 years ago