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BigorU [14]
4 years ago
5

PLEASE NEED HELP ASAP

Chemistry
1 answer:
Zigmanuir [339]4 years ago
8 0

I would love to help but I cant see the picture

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which type of chemical bond would be formed between two elements having electron configuration of 1s2 2s2 2p6 3s2 and 1s2 2s2 2p
OLga [1]
The electron configuration
1
s
2
2
s
2
2
p
6
3
s
2
3
p
2
is the element Silicon.
The key to deciphering this is to look at the last bit of information of the electron configuration
3
p
2
.
The '3' informs us that the element is in the 3rd Energy Level or row of the periodic table. The 'p' tells us that the element is found in the p-block which are all of the Groups to the right of the transition metals, columns 13-18. The superscript '2' tells us that the element is found in the 2nd column of the p-block Group 14.
7 0
3 years ago
From the lists of available reagents select the one(s) you would use to in a preparation of acetophenone (phenyl methyl ketone)
VARVARA [1.3K]

Answer:

Step 1) hydrolysis using NaOH/H2O to form benzylalcohol

Step2) oxidation to Carboxylic acid using KMnO4 followed by decarboxylation to form benzene

3) friedel craft acylation using CH3COCl/AlCl3

Explanation:

The above 3 steps will yield acetophenone from methylbenzoate

3 0
3 years ago
Science / which phrase describes the differences between these two liquid ?
Zina [86]

Answer:

viscosity

Explanation:

one one left is mercury and the other one is honey right?

8 0
3 years ago
The wastewater in your home goes to one of three places. It can run into a home septic system, it can go to a centralized sewage
NemiM [27]

Answer:

                                                 

Explanation:

5 0
3 years ago
Read 2 more answers
You have a solution that is 0.02M formate (HCOO-) and 0.03M formic acid (HCOOH), which has a Ka of 1.8x10-4. What is the pH of t
lisov135 [29]

Answer:

3.6

Explanation:

Step 1: Given data

  • Concentration of formic acid: 0.03 M
  • Concentration of formate ion: 0.02 M
  • Acid dissociation constant (Ka): 1.8 × 10⁻⁴

Step 2: Calculate the pH

We have a buffer system formed by a weak acid (HCOOH) and its conjugate base (HCOO⁻). We can calculate the pH using the <em>Henderson-Hasselbach equation</em>.

pH = pKa +log\frac{[base]}{[acid]} = -log 1.8 \times 10^{-4} + log \frac{0.02}{0.03} = 3.6

6 0
3 years ago
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