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sleet_krkn [62]
4 years ago
11

Electrochemical processes are written with the oxidation half-reaction on the left and the reduction reaction on the right; wher

eas, oxidation-reduction reactions are represented by equations that group the reaction participants into reactants and products.
a. TRUE
b. FALSE
Chemistry
1 answer:
CaHeK987 [17]4 years ago
8 0

Answer:

B) FALSE.

Explanation:

First off, its important to understand the following concepts;

A half reaction is either the oxidation or reduction reaction component of a redox (Oxidation - Reduction) reaction. A half reaction is obtained by considering the change in oxidation states of individual substances involved in the redox reaction.

Often, the concept of half-reactions is used to describe what occurs in an electrochemical cell, such as a Galvanic cell battery. Half-reactions can be written to describe both the metal undergoing oxidation (known as the anode) and the metal undergoing reduction (known as the cathode).

Half equations simply much just breaks the reaction into oxidation and reduction steps (irrespective of the order, whether left or right).

An example of half equation is given below;

Mg → Mg2+ + 2e− (Oxidation)

Cu2+ + 2e− → Cu (Reduction)

The answer is false because; oxidation-reduction reactions are NOT represented by equations that group the reaction participants into reactants and products. Rather they are

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An atom of lead has a radius of and the average orbital speed of the electrons in it is about . Calculate the least possible unc
victus00 [196]

The question is incomplete. Here is the complete question.

An atom of lead has a radius of 154 pm and the average orbitalspeed of the electron in it is about 1.8x10^{8} m/s. Calculate the least possible uncertainty in a measurement of the speed of an electron in an atom of lead. Write your answer as a percentage of the average speed, and round it to significant 2 digits.

Answer: v% = 0.21 m/s

Explanation: To calculate the uncertainty, use <u>Heisenberg's Uncertainty Principle</u>, which states that:  ΔpΔx≥\frac{h}{4\pi }

where h is <u>Planck's constant</u> and it is equal to 6.626.10^{-34}m²kg/s.

Since p (momentum) is p = m.v:

mΔv.Δx ≥ \frac{h}{4\pi }

Δv = \frac{h}{4\pi.x.m }

Given that: r = x = 1.54.10^{-10}m and mass of an electron is m=9.1.10^{-31}kg

Δv = \frac{6.626.10^{-34} }{4.3.14.1.54.10^{-10}.9.1.10^{-31}}

Δv = 0.0376.10^{7}

As percentage of average speed:

Δv.\frac{1}{v}.100% = \frac{0.0376.10^{7} }{1.8.10^{8} }.10² = 0.021.10 = 0.21%

The least possible uncertainty in a speed of an electron is 0.21%.

5 0
4 years ago
A particular reactant decomposes with a half‑life of 113 s when its initial concentration is 0.331 M. The same reactant decompos
algol13

Answer:

The reaction is second-order, and k = 0.0267 L mol^-1 s^-1

Explanation:

<u>Step 1:</u> Data given

The initial concentration is 0.331 M

half‑life time =  113 s

The same reactant decomposes with a half‑life of 243 s when its initial concentration is 0.154 M.

<u>Step 2: </u>Determine the order

The reaction is not first-order because the half-life of a first-order reaction is independent of the initial concentration:

t½ = (ln(2))/k

Calculate k for the two conditions given:

⇒ 113 s with initial concentration is 0.331 M

t½ = ([A]0)/2k

113 s = (0.331 M)/2k

k = 0.00146 mol L^-1 s^-1

⇒ 243 s with an initial concentration is 0.154 M

t½ = ([A]0)/2k

243 s = (0.154 M)/2k

k = 0.000317 mol L^-1 s^-1

The <u>values of k are different</u>, so that rules out zero-order.

<u>Step 3: </u>Calculate if it's a second-order reaction

For a second-order reaction, the half-life is given by the expression

t½ = 1/((k*)[A]0))

<u>Calculate k for the two conditions given: </u>

⇒ 113 s when its initial concentration is 0.331 M

t½ = 1/((k*)[A]0))

113 s = 1/(k*(0.331 M))

k = 1/((0.331 M)*(113 s)) = 0.0267 L mol^-1 s^-1

⇒ 243 s when its initial concentration is 0.154 M

t½ = 1/((k*)[A]0))

243 s = 1/(k*(0.154 M))

k = 1/((0.154 M)*(243 s)) =  0.0267 L mol^-1 s^-1

The values of k are the same, so the reaction is second-order, and k = 0.0267 L mol^-1 s^-1

4 0
4 years ago
A self-contained system within a larger system? *
My name is Ann [436]

Answer:

subsystems.

Explanation:

A self-contained system within a larger system. system. A group of interacting or interdependent elements forming a complex whole, as in all the factors or variables in an environment or all the variables that might affect a science experiment.

4 0
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