2 years ago

Balance each of these equations.

1 answer:

8 0

Answer:

A. 2NO + O2 -> 2NO2

B. 4Co + 3O2 -> 2Co2O3

C. 2Al + 3Cl2 -> Al2Cl6

D. 2C2H6 + 7O2 -> 4CO2 + 6H2O

E. TiCl4 + 4Na -> Ti + 4NaCl

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KonstantinChe [14]

Answer: There are 0.5 grams of barium sulfate are present in 250 of 2.0 M $BaSO_{4}$ solution.

Explanation:

Given: Molarity of solution = 2.0 M

Volume of solution = 250 mL

Convert mL int L as follows.

$1 mL = 0.001 L\\250 mL = 250 mL \times \frac{0.001 L}{1 mL}\\= 0.25 L$

Molarity is the number of moles of solute present in liter of solution. Hence, molarity of the given $BaSO_{4}$ solution is as follows.

$Molarity = \frac{mass}{Volume (in L)}\\2.0 M = \frac{mass}{0.25 L}\\mass = 0.5 g$

Thus, we can conclude that there are 0.5 grams of barium sulfate are present in 250 of 2.0 M $BaSO_{4}$ solution.

7 0

2 years ago

Serggg [28]

Answer:

I don't know but I'm curious now

4 0

2 years ago

kaheart [24]

Answer: 0.20 M

Explanation:

5 0

2 years ago

astraxan [27]

The answer is D . I hope this help you :) .

7 0

1 year ago

horrorfan [7]

I am going to go with,

0.10 g/mL
0.0700 g/mL
0.0447 g/mL

I don't know if this is the correct answer, but I am 80% sure that it may be.
:) :)

6 0

3 years ago