Answer:
0.665
Step-by-step explanation:
Given: 100 people are split into two groups 70 and 30. I group is given cough syrup treatment but second group did not.
Prob for a person to be in the cough medication group = 0.70
Out of people who received medication, 34% did not have cough
Prob for a person to be in cough medication and did not have cough
=
Prob for a person to be not in cough medication and did not have cough
=
Probability for a person not to have cough
= P(M1C')+P(M2C')
where M1 = event of having medication and M2 = not having medication and C' not having cough
This is because M1 and M2 are mutually exclusive and exhaustive
SO P(C') = 0.397+0.2=0.597
Hence required prob =P(M1/C') = 
Answer:
Multiply first. PEMDAS - Parenthesis, Exponents, Multiplication, Divison, Addition, Subtraction.
Step-by-step explanation:
15 - 8 = 4 x 7
6 = 36
1) this is simply solving it, so if you divide 16 by 3, you end up getting 5 1/3
2) 3 1/2, by multiplying 7 by 1/2
3) 224, by multiplying 14 by 16
4) 54 mph, by dividing 324 by 6
5) blue, because only the 1/4 ribbon color would be collected after 3/4 mile
6) 7/8 - 3/8 equals 4/8, or 1/2 when simplified